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Ket [755]
3 years ago
9

Sam has a water bottle that holds 250 milliliters of water when full. He needs to fill a 5-liter water jug for his team. If Sam

uses the water bottle to fill the jug, how many times does he need to fill the water bottle in order to fill the jug? ​

Mathematics
2 answers:
Georgia [21]3 years ago
7 0
He would have to fill the water bottle 20 times in order to fill the jug
stealth61 [152]3 years ago
5 0
There are 1000ml in 1L. There for there are 4x250ml in 1L. Multiply 5x4 gives you 20. Therefore he needs to fill 20 water bottles to fill the jug
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2.85 rounded to the nearest hundredth <br> A. 2.861<br> B. 2.849<br> C. 2.842<br> D. 2.805
blagie [28]

Answer:

B) 2.849

Step-by-step explanation:

Given: 2.85 which is rounded to the nearest hundredth place.

To find the number, the thousandth place must be greater than or equal to 5.

Here 2.849 has the thousandth place greater than 5

When we round off 2.849 to the nearest hundredth place, we get

2.85

Therefore, answer is B) 2.849

Hope this will helpful.

Thank you.

5 0
3 years ago
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What's the slope of (-5, -3) and (5,3)
MAVERICK [17]

Answer:

10/6

Step-by-step explanation:

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(5--5)/(3--3)

and 2 negatives are a positive so it would turn to

5+5/3+3   or    10/6

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8 0
3 years ago
I need help solving it
blagie [28]
X2-64=0
x2=64

x=8 because when multiplied by itself, and plugged back in, it works
8 0
3 years ago
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ASAP!!!!!!!!! PLEASE help me with this question! This is really urgent! No nonsense answers please.
Vesna [10]

Answer:

Because <CBD is an inscribed angle and <CAD is a central angle with the same intercepted arc, m<CBD = 55°, or half of the measure of <CAD.

Step-by-step explanation:

The Inscribed Angle Theorem proves that an inscribed angle is half the measure of a central angle, if both the inscribed angle and the central angle intercepts the same arc.

Also, according to the inscribed angle theorem, an inscribed angle is ½ of the measure of the arc it intercepts.

Therefore, m<CBD is half of m<CAD, or half of the measure of the arc CD that they both intercept together.

Thus, m<CBD = 55°, which is ½ of m<arc CD.

m<arc CD = 110° = m<CAD.

m<CBD = ½ of m<CAD = 55°.

The statement that best describes the relationship between <CBD and <CAD is "Because <CBD is an inscribed angle and <CAD is a central angle with the same intercepted arc, m<CBD = 55°, or half of the measure of <CAD."

4 0
2 years ago
Please help me answer this question its urgent
yarga [219]

Answer:

Step-by-step explanation:

1). \frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+2\frac{2}{9}n

= \frac{2}{3}n-\frac{3}{4}n+\frac{1}{6}n+(2+\frac{2}{9})n

= (\frac{2}{3}-\frac{3}{4}+\frac{1}{6})n+(2+\frac{2}{9})n

= (\frac{8}{12}-\frac{9}{12}+\frac{2}{12})n+(2+\frac{2}{9})n

= \frac{(8-9+2)}{12}n+(2+\frac{2}{9})n

= \frac{1}{12}n+(2+\frac{2}{9})n

= (\frac{1}{12}+2+\frac{2}{9})n

= (\frac{3}{36}+\frac{72}{36}+\frac{8}{36})n

= \frac{83}{36}n

= 2\frac{11}{36}n

2). \frac{2}{5}g-\frac{1}{6}-g+\frac{3}{10}g-\frac{4}{5}

= (\frac{2}{5}-1+\frac{3}{10})g-(\frac{1}{6}+\frac{4}{5})

= (\frac{4}{10}-\frac{10}{10}+\frac{3}{10})g-(\frac{5}{30}+ \frac{24}{30})

= (\frac{4-10+3}{10})g-(\frac{5+24}{30})

= \frac{-3}{10}g-\frac{29}{30}

= -\frac{3}{10}g-\frac{29}{30}

3). i+6i-\frac{3}{7}i+\frac{1}{3}h+\frac{1}{2}i-h+\frac{1}{4}h

= 7i-\frac{3}{7}i+\frac{1}{2}i+\frac{1}{3}h-h+\frac{1}{4}h

= (7-\frac{3}{7}+\frac{1}{2})i+(\frac{1}{3}-1+\frac{1}{4})h

= (\frac{98}{14} -\frac{6}{14}+\frac{7}{14})i+(\frac{4}{12}-\frac{12}{12}+\frac{3}{12})h

= (\frac{98-6+7}{14})i+(\frac{4-12+3}{12})h

= \frac{99}{14}i-\frac{5}{12}h

6 0
3 years ago
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