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4 years ago

Escribir una funcion cuadratica f cuyos ceros sean -13 y -2 por favor ayudaaa

Mathematics

1 answer:

Aleks [24]4 years ago

4 0

Answer:

x²+15x+26

Step-by-step explanation:

zeros are x=-13, x=-2

x=-13 then x+13=0

x=-2 then x+2=0

(x+13) (x+2)

x²+15x+26

y=ax²+bx+c

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2. The sum of two numbers is 30. Determine the two numbers if their product is a maximum.

SCORPION-xisa [38]

Answer:

X+y=30

X=30-y

Z=yx

Z=y(30-y)

D/dy

z=30–2y

At max 30–2y=0

2y=30 Y=15

Therefore x=15

Step-by-step explanation:

5 0

3 years ago

Lin's teacher uses the box to store her set of cubes with an edge length of one half inch. if the box is completely full, how ma

nlexa [21]

Answer:

448 cubes

Step-by-step explanation:

Volume of cubes fitted in the box will be equal to the cumulative volume of the cubes.

Since, volume of a cube = (Side)³

Side of the cube = $\frac{1}{2}$ inch

Therefore, volume of the cube = $(\frac{1}{2})^3=\frac{1}{8}$ inches

Volume of the storage box = 56 cubic inches

Since, number of cubes fitted in the storage box = $\frac{\text{Volume of the storage box}}{\text{Volume of one cube}}$

= $\frac{56}{\frac{1}{8}}$

= 56 × 8

= 448 cubes

Therefore, number of cubes fitted in the storage box = 448

3 0

3 years ago

Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum

const2013 [10]

Answer: The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

$S=\sum_{i=1}^{\infty}15(4)^{i-1}.$

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, $\sum_{i=1}^{\infty}a_i$ is an infinite series, with complex coefficients $a_i$ and we consider the following limit:

$L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.$

Then, the series will be convergent if L < 1 and divergent if L > 1.

For the given series, we have

$a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.$

So, the limit is given by

$L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.$

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0

4 years ago

Read 2 more answers

What is 65 5/6+ 6 4/6 in simplest form?

juin [17]

72.5 as decimal or 72 1/2 as fraction

8 0

4 years ago

Quation that show an estimate of 7,203+299

Dmitry [639]

The two numbers are very near 7200 and 300. The sum of those is a good estimate of your sum:

... 7200 + 300 = 7500

_____

If you're taught methods of addition that include "make a ten" or "make a hundred", you know you can "borrow" a 1 from 7203 (making it 7202) and loan that 1 to 299 to make it 300. Now, you know your sum is exactly 7202+300 = 7502, with no estimation necessary.

8 0

3 years ago

Read 2 more answers