Answer:
Step-by-step explanation:
You are being asked to compare the value of a growing infinite geometric series to a fixed constant. Such a series will always eventually have a sum that exceeds any given fixed constant.
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<h3>a)</h3>
Angelina will get more money from the Choice 1 method of payment. The sequence of payments is a (growing) geometric sequence, so the payments and their sum will eventually exceed the alternative.
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<h3>c)</h3>
For a first term of 1 and a common ratio of 2, the sum of n terms of the geometric series is given by ...
Sn = a1×(r^n -1)/(r -1) . . . . . . . . . . series with first term a1, common ratio r
We want to find n such that ...
Sn ≥ 1,000,000
1 × (2^n -1)/(2 -1) ≥ 1,000,000
2^n ≥ 1,000,001 . . . . add 1
n ≥ log(1,000,001)/log(2) . . . . . take the base-2 logarithm
n ≥ 19.93
The total Angelina receives from Choice 1 will exceed $1,000,000 after 20 days.
Answer:
B) A < 0
Step-by-step explanation:
I had the same question, and got it right.
Answer:
6
Step-by-step explanation:
(2.4×10³)×(3×10^x)=7.2×10^9
(3x10^x)=(7.2×10^9)/(2.4×10^3)
3×10^x=3×10^6
10^x=10^6
*when bases are same ,powers are equated*
thus x=6
Answer:
0.3333
Step-by-step explanation:
Detecting...<span>
</span>Your answer would be:
