two passenger train traveling in opposite directions meet and pass each other. Each train is 1/18 miles long and is traveling at
40 miles per hr. How many seconds after the front parts of the trains will meet their rear parts pass each other.
1 answer:
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Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
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√(x₁-x₂) +(y₁-y₂)
=√(38-14) +(30-20)
=√24+10
=√34
You take 69 * 0.35 and then take that total (24.15) so 60-24.15= 35.85 then to find the tax take 35.85*.07=2.51 so your answer is 35.85+2.51=38.36
