Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.
Answer:
24
Step-by-step explanation:
I think you ask about LCM
6- 2×3
8- 2×2×2
lcm = 2×2×2×3 = 24
Answer:
0.9958
Step-by-step explanation:
P(being correct) = 1/4 = 0.25
Hence, p = 0.25
n = 19
P(x ≥ 1) = p(x = 1) + p(x = 2) +... + p(x = 19)
Using the binomial probability formula :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
However, to save computation time, we could use a calculator :
Using a calculator,
P(x ≥ 1) = 0.99577
P(x ≥ 1) = 0.9958
Answer:
$15.75
Step-by-step explanation:
y × 100 = 5 × 15
100y = 75
100y ÷ 100 = 75 ÷ 100
y = 0.75
$15 - $0.75
$14.25
y × 100 = 10 × 15
100y = 150
100y ÷ 100 = 150 ÷ 100
y = 1.5
$14.25 + $1.50
$15.75
Answer:
b = d -wn
Step-by-step explanation:
b = d -wn
Here, n is an independent variable and b is an dependent variable in an linear relation, and d and w are two constant values.
Hope it will find you well.
