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solniwko [45]
3 years ago
9

Help pls!! .........................................................................

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

a)8

b)13

Step-by-step explanation:

a) ar = c

a^2+b^2=c^2

4^2+7^2=c^2

16+49 = c2

c = \sqrt{65} ~8

b) sa= c

a2+b2=c2

7^2 + (15-4)^2

49+121 = c2

c= \sqrt{170} = 13

I hope im right!!

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Solve the following pair of equations by elimination method: x+y=4, 2x+y=3​
allsm [11]

Answer:

x = 1

y = 5

Step-by-step explanation:

x + y = 4 __ (1)

2x + y = 3 __ (2)

equation (1) x 2, (2) x 1

2x + 2y = 8

2x + y = 3

0  + y = 5

y= 5 (ANS)

x + y = 4

x + 5 = 4

x = 5 - 4

x = 1 (ANS)

I HOPE MY ANSWER IS CORRECT IF NOT I APOLOGIZE.

5 0
2 years ago
WXY is a right triangle. <br><br> A. True. <br> B. False.
lora16 [44]

Answer:

B. False


Step-by-step explanation:

According to pythagorean theorem, for this to be a right triangle, the sum of  square of the length of the two legs must equal square of the length of the hypotenuse (longest side).

So  (\sqrt{34} )^{2}  should equal  (\sqrt{18} )^{2}+(\sqrt{18} )^{2}

  • <em>We also know that  (\sqrt{a} )^{2}=(\sqrt{a})(\sqrt{a})=a</em>

Hence,  (\sqrt{18} )^{2}+(\sqrt{18} )^{2}=18+18=36  , and

(\sqrt{34} )^{2}=34

They ARE NOT EQUAL, so the triangle is NOT a right triangle.

5 0
3 years ago
Read 2 more answers
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
Solve the inequality (-3,-3) (3,-1) on a graph
Firdavs [7]
The first number is x axis while the second is y

5 0
4 years ago
Nicole works Monday through Friday and make $250 for her efforts. How much money does she make per day?
bixtya [17]

Answer:

$50 per day

Step-by-step explanation:

she works five days in week and she gets 250 bucks

250/5=50

5 0
3 years ago
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