Question

Subtract-3c2 + 12cd – 4d2 from 4c2 + 3cd + 2d?.

Answer 1

Answer:

Subtract $-3c^2 + 12cd - 4d^2$ from $4c^2 + 3cd + 2d^2$ we get $\mathbf{7c^2-9cd+6d^2}$

Step-by-step explanation:

We need  to Subtract $-3c^2 + 12cd - 4d^2$ from $4c^2 + 3cd + 2d^2$

(Note: Considering 2d^2 instead of 2d as thinking it typo error)

Subtracting from means we have to subtract $4c^2 + 3cd + 2d^2 -(-3c^2 + 12cd - 4d^2)$

Subtracting:

$4c^2 + 3cd + 2d^2 -(-3c^2 + 12cd - 4d^2)\\=4c^2 + 3cd + 2d^2 +3c^2 - 12cd + 4d^2$

Combining like terms (Like terms are those that have same variables like 4c^2 and 3c^2 are like terms, 3cd and -12cd are like terms, 2d^2 and 4d^2 are like terms)

$=4c^2+3c^2 + 3cd-12cd + 2d^2+4d^2 \\=7c^2-9cd+6d^2$

So, Subtract $-3c^2 + 12cd - 4d^2$ from $4c^2 + 3cd + 2d^2$ we get $\mathbf{7c^2-9cd+6d^2}$