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Pavlova-9 [17]
2 years ago
10

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 2 large boxes and 6 small boxes has a t

otal weight of 128 kilograms. A delivery of 5 large boxes and 3 small boxes has a total weight of 137 kilograms. How much does each type of box weigh?
Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0

Large box weighs 18.25 kilograms and small box weighs 15.25 kilograms.

Step-by-step explanation:

Let,

Large box = x

Small box = y

According to given statement;

2x+6y=128    Eqn 1

5x+3y=137     Eqn 2

Multiplying Eqn 2 by 2;

2(5x+3y=137)\\10x+6y=274\ \ \ \ Eqn\ 3

Subtracting Eqn 1 from Eqn 3

(10x+6y)-(2x+6y)=274-128\\10x+6y-2x-6y= 146\\8x=146

Dividing both sides by 8

\frac{8x}{8}=\frac{146}{8}\\x=18.25

Putting x=18.25 in Eqn 1

2(18.25)+6y=128\\36.5+6y=128\\6y=128-36.5\\6y=91.5

Dividing both sides by 6

\frac{6y}{6}=\frac{91.5}{6}\\y=15.25

Large box weighs 18.25 kilograms and small box weighs 15.25 kilograms.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/7287774
  • brainly.com/question/726990

#LearnwithBrainly

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How many really solutions does 4a^2 = 8a− 4 have
creativ13 [48]

Answer:

It has one solution which is a=1

4 0
2 years ago
A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say <em>E </em>occurring is:

P (E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let <em>X</em> = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, <em>n</em> = 20.

Number of defective electric toothbrushes is, <em>x</em> = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

{20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

{3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

                                                            =\frac{3}{190}\\

                                                            =0.01579\\\approx0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0
3 years ago
Please help me solve this: 6 1/3 + k + 3 5/6 + 5 1/2 = 26 1/6
attashe74 [19]
6 1/3 + k + 3 5/6 + 5 1/2 = 26 1/6 
Add your fractions 
6 1/3 + 3 5/6 + 5 1/2 = 15 2/3
now You need to isolate k on one side of the equation by using the subtraction method of equality.
k + 15 2/3 = 26 1/6
k = 10 1/2 

Hope this helps

I had to edit
5 0
3 years ago
Read 2 more answers
Let x be the ages of students in a class. Given the frequency distribution f(x) above, determine the following probabilities:.
lora16 [44]

Probabilities are used to determine the chances of events

The value of the probability P(x < 24) is 0.7895

<h3>How to calculate the probability P(x < 24)?</h3>

This is calculated as:

P(x < 24) = \frac{n(x < 24)}{Total}

So, we have:

P(x < 24) = \frac{22 + 3 + 5}{22 + 3 + 5 + 4 + 4}

Evaluate the sums

P(x < 24) = \frac{30}{38}

Evaluate the quotient

P(x < 24) = 0.7895

Hence, the value of the probability P(x < 24) is 0.7895

Read more about probabilities at:

brainly.com/question/9385303

8 0
2 years ago
ET
ANEK [815]

Answer:

<h2>INFO</h2>

Step-by-step explanation:

NEED MORE INFO...

8 0
3 years ago
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