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PSYCHO15rus [73]
3 years ago
5

?...............................

Mathematics
1 answer:
arsen [322]3 years ago
5 0

Answer:

-2 ≤ n < 8

Step-by-step explanation:

_________________

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Write 2.04 × 10 ⁴ as an ordinary number
ivann1987 [24]

Answer:

20400

Step-by-step explanation:

its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400

8 0
2 years ago
Solve:<br><br>1/5c =15<br><br>c=__<br>solve what c equals
grin007 [14]

Answer:

75

Step-by-step explanation:

a fifth of c is 15

75÷5=15

4 0
4 years ago
How to graph y=-3x+15
steposvetlana [31]

Answer:

Well first you put the y-intercept on the graph. In this case it would be 15

So graph the point (0,15)

The you do the slope which is 3

so you always do rise over run for slope.

If 3 were a fraction it would be 3/1 so go up 3 points and the go right 1 point from (0,15)

hope this helps .-.

3 0
3 years ago
Alma ask money to buy a bicycle of $150. his mom give him $40 at the moment and gives kyle $10 each month to pay the total of th
Tanya [424]

Answer: $40+$10x

Step-by-step explanation:

1. We already know he has $40.

2. 10x represent the 10 dollars he is paid per month.

5 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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