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Sindrei [870]
3 years ago
12

If y varies directly as x, and y = -85 when x = 5, what is the value of y when x = 19

Mathematics
2 answers:
ziro4ka [17]3 years ago
3 0

Answer:

-323

Step-by-step explanation:

y varies x

make k the unknown

y=kx

-85= 5k

:• k = -17

when x= 19

we can say...

y= -17(19)

y = -323 ✓

beks73 [17]3 years ago
3 0
8.56 is the answer ...........
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Ethan writes 2/3 of a page in 5/12 of a minute. How much time does it take him to write one page
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2/3 of a page in 5/12 of a minute

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\frac{2}{3} \times \frac{3}{2} = 1

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So, Ethan can read 1 page in 5/8 of a minute.
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Any number from -10 to -∞ would be correct. One example is -79.
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For each set of probabilities, determine whether the events A and B are independent or dependent.
lozanna [386]

Answers:

  • (a) Independent
  • (b) Dependent
  • (c) Dependent
  • (d) Independent

========================================================

Explanation:

If events A and B are independent, then the two following equations must both be true

  • P(A | B) = P(A)
  • P(B | A) = P(B)

This is because the conditional probability P(A|B) means "P(A) when B has happened". If B were to happen, then P(A) must be the same as before. In other words, event B does not affect A, and vice versa.

For part (a), we have P(B) = 1/4 and P(B|A) = 1/4 showing that P(B|A) = P(B) is true, and therefore we can say the events are independent. We don't need the info that P(A) = 1/8.

------------------------

Unlike part (a), part (b) has the answer "dependent" because P(A) = 1/8 and P(A | B) = 1/3 differ in value. Event A starts off at probability 1/8, but then event B occurring means P(A) gets increased to 1/3. The prior knowledge about B changes the chances of A. The P(B) = 1/5 is unneeded.

------------------------

If A and B were independent, then,

P(A and B) = P(A)*P(B)

However,

P(A)*P(B) = (1/4)*(1/5) = 1/20

which is not the same as P(A and B) = 1/6. Therefore the two events are dependent.

------------------------

Refer back to part (a)

P(A) = 1/4 and P(A|B) = 1/4 are identical in value, so P(A|B) = P(A) which leads to the events being independent. Whether we know event B happened or not, it does not affect the outcome of event A. P(B) = 1/9 is unneeded.

7 0
2 years ago
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