ASAP!!! Is the relation in the table below a function?

Mathematics

1 answer:

statuscvo [17]2 years ago

4 0

Answer:

Step-by-step explanation:

A relation is a function if every x-value has exactly one y-value.

Because the x-value 1 has two y-values (-3 and 3), the relation is not a function.

Plotting (1, -3) and (1, 3) will produce a vertical line that intersects the function at two points.

Therefore, the relation is not a function.

Hope that helps.

You might be interested in

Which one is the answer?

Arada [10]

Answer: I think it’s the one you picked which is D. I might make a mistake, but don’t worry. You will be fine.

Step-by-step explanation: I learnt it at tutoring and not at school.

3 0

3 years ago

iDentify the equation of the circle that has its center at (-27, 120) and passes through the origin A. (x−27)2+(y+120)2=123 B. (

melomori [17]

The equation of a circle is given in the form $(x-a)^2+(y-b)^2=r^2$ , where

(a, b) is the centre of the circle
r = radius

We have the centre of the circle (-27, 120)
We can work out the radius by modelling the radius as the hypotenuse of a triangle as shown in the diagram below

$r^2=27^2+120^2$
$r^2 = 15129$

The equation of the circle is

$[x-(-27)]^2+[y-120]^2=15129$
$[x+27]^2+[y-120]^2=15129$

Correct answer: option number 4