Question

The manager of an accounting department wants to form a two

Answer 1

Answer: 153

Step-by-step explanation:

When we have a group of N elements, the total number of combinations of K elements ( K ≤ N) is:

$C (N, K) = \frac{N!}{(N-k)!*K!}$

Where N! = N*(N - 1)*(N - 2)*...*2*1

In this case, we have a group of 18 people (then N = 18) and we want to see how many different combinations of 2 we can make (K = 2).

Using the above equation we get:

$C(18, 2) = \frac{18!}{(18 - 2)!*2!} = \frac{18!}{16!*2!} = \frac{18*17}{2} = 9*17 = 153$

There are 153 different ways in which the manager can do this.