All categories

2 years ago

A line's slope is 1/5 the y-intercept is 5. What is the equation in slope-intercept form?

Mathematics

1 answer:

damaskus [11]2 years ago

7 0

Answer: y = 1/5x+5

Step-by-step explanation: Slope intercept form is y = mx+b, where m is the slope, and b is the y intercept. Substitute accordingly.

You might be interested in

Solve: The quantity 3 x minus 15 divided by 2 = 4x

Trava [24]

X = -3
i hope this helps

5 0

3 years ago

Read 2 more answers

Answer the question in the photo

Artemon [7]

The answer for this question is -20.You have to subtract -15-5 and that’s what you get.

7 0

3 years ago

Read 2 more answers

Which number sentence matches the question below?

Aleksandr [31]

The answer would be B. (228-89) because you are trying to find the difference.

5 0

2 years ago

A. 28 <br> B. b - 28 <br> C.b + 28<br> D.b

NISA [10]

Answer:

b - 28

Step-by-step explanation:

If she gives away 28 buttons that means she subtracts 28 from the amount she had

b - 28 is what she has left

6 0

2 years ago

A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the

creativ13 [48]

Answer:

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

$2r+s=18$

$s=r \theta$

$2r+r \theta=18$

solve for r

$r=\frac{18}{2+\theta}$

step 2

Find the value of s

$s=r \theta$

substitute the value of r

$s=\frac{18}{2+\theta}\theta$

step 3

we know that

The area of complete circle is equal to

$A=\pi r^{2}$

The complete circle subtends a central angle of 2π radians

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

$\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}$

substitute the value of r

$A=\frac{(\frac{18}{2+\theta})^2\theta}{2}$

$A=\frac{162 \theta}{(\theta+2)^2}$

Convert to function notation

$A(\theta)=\frac{162 \theta}{(\theta+2)^2}$

6 0

3 years ago