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Vladimir79 [104]
3 years ago
14

The formula for the area of a trapezold with altitude k and bases m and n is A=k/2(m+n)

Mathematics
1 answer:
Ghella [55]3 years ago
7 0

Answer:

m=\frac{2A-kn}{k}

Hence, option C is true.

Step-by-step explanation:

Given the expression

A=\frac{k}{2}\left(m+n\right)

Solving for 'm'

A=\frac{k}{2}\left(m+n\right)

Flip the equation

\frac{k}{2}\left(m+n\right)=A

Expanding by applying the distributive law: a\left(b+c\right)=ab+ac

\frac{1}{2}km+\frac{1}{2}kn=A

Add (-1)/2 × kn to both sides

\frac{1}{2}km+\frac{1}{2}kn+\left(-\frac{1}{2}kn\right)=\left(-\frac{1}{2}kn\right)+A

simplify

\frac{1}{2}km=-\frac{1}{2}kn+A

Divide both sides by k/2

\frac{\frac{1}{2}km}{\frac{k}{2}}=\frac{-\frac{1}{2}kn+A}{\frac{k}{2}}

m=\frac{2A-kn}{k}

Therefore,

m=\frac{2A-kn}{k}

Hence, option C is true.

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-19/36

Step-by-step explanation:

We can find the slope using

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m = ( 94-56)/( 28 -100)

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Evaluate the following double integral where a = 2y
Keith_Richards [23]

Change the order of integration.

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Substitute u=x^2 and du=2x\,dx.

\displaystyle \frac12 \int_0^2 x \cos(x^2) \, dx = \frac14 \int_0^4 \cos(u) \, du = \frac14 \sin(u) \bigg|_{u=0}^{u=4} = \boxed{\frac{\sin(4)}4}

4 0
11 months ago
$7000 is compounded semiannually at a rate of 11% for 21years Find the total amount and round to the nearest cent
photoshop1234 [79]

\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
\\
\text{we know that the amount after t year when compounded is given by}\\
\\
A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
\\
\text{here P is the principal amoount, so }P=7000,\\
\\
\text{r is the interest rate, }r=11\%=0.11\\
\\
\text{n is the number of times in a year, here semiannulay, so }n=2,\\
\\
\text{and t is the time, so }t=21\\
\\
\text{so the amount after 21 years is}

A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
\\
\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
\\
\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
\\
\Rightarrow A\approx 66328.68

So the amount after 21 years is: $66328.68

7 0
3 years ago
A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π
Ratling [72]

Answer:

11\dfrac{13}{25}\pi

Step-by-step explanation:

r = Radius of semicircle = 2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}

Area of semicircle is given by

A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}

The area of the semicircle is 11\dfrac{13}{25}\pi\ \text{sq. units}.

4 0
3 years ago
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