A.Calculate the mean,median and mode.(3 points each) 1.)1,2,3,4,5 2.)2,3,4,5,6,6 3.)6,7,5,4,5,6,2,5
zlopas [31]
Answer:
Step-by-step explanation:
1.)1,2,3,4,5
mean=sum of all values/number of values
=1+2+3+4+5/5
=15/5
mean=3
Mode :
In the given data, no observation occurs more than once.
Hence the mode of the observations does not exist, means mode=0.
Median
1,2,3,4,5
Middle value is 3 so the median is 3.
2.)2,3,4,5,6,6
mean=sum of all values/number of values
=2+3+4+5+6+6/6
=26/6
mean =4.33
Mode
is that value of the observation which occurs maximum number of times so here mode is 6.
Median
2,3,4,5,6,6
4+5/2
9/2
median=4.5
3.)6,7,5,4,5,6,2,5
mean=sum of all values/number of values
=6+7+5+4+5+6+2+5/8
=40/8
mean =5
Mode
is that value of the observation which occurs maximum number of times so here mode is 5
Median
2,4,5,5,5,6,6,7
5+5/2
10/2
median=5
Answer:
5 and 35
Step-by-step explanation:
Answer:
P=30cm
Step-by-step explanation:
So the formula there is to find the Perimeter of the rectangle, so we are going to use it!
Using Substitution:
![A=2L+2W\\A=2(10)+2(5)\\A=20+10\\A=30](https://tex.z-dn.net/?f=A%3D2L%2B2W%5C%5CA%3D2%2810%29%2B2%285%29%5C%5CA%3D20%2B10%5C%5CA%3D30)
Hope this helps!
Stay Safe!
Answer:
![y=\frac{x}{3}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bx%7D%7B3%7D)
Step-by-step explanation:
<u><em>The question is</em></u>
Solve for y
we have
![x=3y](https://tex.z-dn.net/?f=x%3D3y)
Solve for y
That means ---> isolate the variable y
Divide by 3 both sides
![\frac{x}{3}=\frac{3y}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%3D%5Cfrac%7B3y%7D%7B3%7D)
Simplify right side
![\frac{x}{3}=y](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%3Dy)
Rewrite
![y=\frac{x}{3}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bx%7D%7B3%7D)
therefore
Your answer is correct
Answer:
i) 1.25m
ii) 32 books
Step-by-step explanation:
60 identical books occupies = length of 1.5m
(i) the length occupied by 50 such books on
a shelf,
If:
60 books = 1.5m
50 books = y m
60 × ym = 1.5 × 50
ym = 1.5 × 50/60
= 1.25 m
Therefore, 50 of such books occupies a length of 1.25m
(ii) the number of such books needed to completely
occupy a shelf that is 80 cm long.
100 cm = 1m
80 cm = x m
Cross Multiply
xm = 80/100
= 0.8 m
If : 1.5 m = 60 books
0.8 m = y books
Cross Multiply
= 1.5m × y books = 60 books × 0.8m
y books = 60 books × 0.8m/1.5m
y books = 32 books
Therefore, 32 books occupies a shelf that is 80 cm or 0.8 m long