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kumpel [21]
3 years ago
13

(6y-7)(3y+1) = 18^y+27y+7y?

Mathematics
1 answer:
garik1379 [7]3 years ago
3 0

Answer:

18y²-15y-7

Step-by-step explanation:

6y×3y-7×3y+6y×1-7×1

=18y²-21y+6y-7

=18y²-15y-7

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Step-by-step explanation:

Solve 4^x=17

x is in the exponent...  so the only operation to bring the x down is the Logarithm

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then   x* log 4 = log 17

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4 years ago
Lex was chatting with his friends thomas and mike. He was wondering how much it will cost him to take a taxi from his house to w
UNO [17]

Answer:

$28.3

Step-by-step explanation:

x=rate for 1km

y=initial fee

Mike: $35 for 15km -> 35 = 15x + y

Thomas: $24.50 for 10km -> 24.50 = 10x + y

Using those two equations we see the following:

Mike paid $10.5 more for 5 more km. The initial fee remains unchanged, so we can calculate the rate for 1km, which is 10.5/5=2.1.

35 = 15x + y

24.50 = 10x + y

10.5 = 5x

2.1=x

Using that value with one of the original equations we can calculate the initial fee.

35 = 15x + y

35 = 15*2.1 + y

35 = 31.5 + y

3.5 = y

Mike paid 15*2.1=31.5 ($2.1 for every km) plus the initial fee, his total was $35.

We subtract the 31.5 from the 35(total) and get the initial fee, which is $3.5.

<u>Let's see what Lex will pay:</u>

Km travelled times 2.1 (the rate for 1km) plus 3.5 (the initial fee).

12*2.1 + 3.5 = 28.3

Lex will pay $28.3 for the same taxi company to travel 12 km.

6 0
3 years ago
Read 2 more answers
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