The gradient of the perpendicular line would be the negative reciprocal of the original line. Therefore the gradient of the perpendicular line would be -2/5x.
Since we know y=mx+c, ∴y=-2/5x+c. Sub in the x and y values of the given point and we get that c=26/5.
The perpendicular equation would be y=-2/5x+26/5.
I hope I got this right.
1600<2570-125.5x<2000 subtract 2570 from all terms...
-970<-125.5x<-570 divide all terms by -125.5 (and reverse signs because of division by a negative!)
7.73>x>4.54 and x is months since January, and since months can only be integers...
x=[5,7]
So January + 5, 6, and 7 respectively are the three months that satisfy the equation...
June, July, and August.
<u>By substitution method </u>
5x - 3y =1
3x + 2y = 1
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I hope I helped you^_^
Okay, so this is actually relatively simple:
Go up 44 units on the y-axis, where x=0, and put a point. Now, since the slope is 3x, you move 3 units up, and 1 unit right, and place a point. Do this about 3 times, continuing to make points up 3, over 1. You can also move 3 units down and 1 unit left from the point at (0,44) because by moving down, you move -3 units, and by moving left, you move -1 units. This causes the negatives to cancel out, and you keep the slope of 3.
I hope this explanation makes sense; good luck!
To solve algebraically:
Plug in any number for x, besides 0 because the y-intercept is (0,44). We will use 1 for our x.
y=44+3x
y=44+3(1)
y=44+3
y=47
And so, (1, 47) would be our point
You can use -1, as well.
y=44+3(-1)
y=44-3
y=41
(-1, 44) would be our point
Your answer would be <u>Ninety seven and sixty ninths.</u> Hope this helps!
