HELP HELP WILL MARK RIGHT AND FIRST ANWSSER BRANLIEST
1 answer:
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Answer:
Step-by-step explanation:
<u><em>( 8 ).</em></u> m∠1 = m∠ 4 = m∠ 5 = <em>m∠6 = 52°</em>
<em><u>( 9 ).</u></em> m∠ 2 = m∠ 3 = <em>m∠ 7</em> = m∠ 8 = 180° - 52° <em>= 128°</em>
Calling x and y the two sizes of the rectangular field, the problem consists in finding the minimum values of x and y that give an area of 
.
The area is the product between the two sizes:
(1)
While the perimeter is twice the sum of the two sizes:
(2)
From (1) we can write
and we can substitute it into (2):
To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:
The derivative of the perimeter is
If we require p'(x)=0, we find
And the other side is
This means that the dimensions that require the minimum amoutn of fencing are (424.26 m, 424.26 m), so it corresponds to a square field.
The area is the product between the two sizes:
While the perimeter is twice the sum of the two sizes:
From (1) we can write
and we can substitute it into (2):
To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:
The derivative of the perimeter is
If we require p'(x)=0, we find
And the other side is
This means that the dimensions that require the minimum amoutn of fencing are (424.26 m, 424.26 m), so it corresponds to a square field.