When a family faces a situation that is too hard to solve by itself, it is a sign of strength to ask for help.
Answer:
In acid-fast staining, carbon fuchsin is used as a primary stain which dissolves the mycolic acid present in the cell wall of <em>Mycobacterium smegmatis </em>and penetrates through it which results in staining <em>Mycobacterium</em> red.
Staphylococcus aureus cell wall does not contain mycolic acid so carbon fuchsin does not penetrate its cell wall, therefore, it becomes colorless after destaining with acid alcohol.
After destaining step methylene blue is added to stain non-acid-fast bacteria blue. So if I mistakenly forgot to use methylene blue during the procedure <em>Mycobacterium smegmatis</em> will appear red due to carbon fuchsin present in their cell wall and S<em>taphylococcus aureus</em> will appear colorless because it is destained.
Answer:
- Glycine
- Ribulose 1,5-bisphosphate
- 3-phosphoglycerate
- Glyceraldehyde 3-phosphate.
- Glucose
- Sucrose
Explanation:
The glycine, among other amino acids, helps to improve chlorophyll production and promotes the process of photosynthesis.
<u>Calvin cycle</u>
During the carbon fixation phase, a CO² molecule combinate with a ribulose 1,5-bisphosphate to form 6-carbonated molecules, which will divide into two 3-phosphoglycerate molecules.
During the reduction phase, NADPH donates its electrons to reduce 3-phosphoglycerate molecules, and turn them into glyceraldehyde 3-phosphate.
During the regeneration phase, a glyceraldehyde 3-phosphate molecule leaves the cycle and goes to the cytosol to form glucose. This step can be done when three CO² enter the cycle and produce six glyceraldehyde 3-phosphate molecules. One of them leaves the cycle to form glucose, while the other five are recycled.
<u>Cytosol: </u>
Once in the cytosol, glyceraldehyde 3-phosphate molecules are used to form glucose and fructose. These two molecules are the monosaccharides that form the sucrose.
Once sucrose is formed, it is transported from the photosynthetic tissues to different parts of the plant by the phloem.
Answer:
The correct answer is D. maintain membrane fluidity through its disruption of fatty acid packing.
Explanation:
<u>Cholesterol</u> is a steroid lipid and is a constituent of biological membranes. It regulates the <em>fluidity</em> of the membrane (so, option C is not correct). Since cell membranes are composed of another type of lipids, the phospholipids, which form a bilayer, cholesterol distributes between the phospholipid tails and avoids these molecules pack each other forming rigid clusters. Thus, the option which better explains the effect is <em>D. maintain membrane fluidity through its disruption of fatty acid packing.</em>
Answer:
A dam that could allow fish to still pass through is a fishway/fish pass its a "fish ladder" that is structured on or around artificial or natural barriers to allow for fishes natural migration and the movement for potamodromous species.
