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3 years ago

What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)

Mathematics

1 answer:

kotegsom [21]3 years ago

4 0

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

$l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2) \right )^{2}+\left (6-2 \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}$

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

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2 years ago

Marla has 1\2 of a pound of candy. She equally distributes the candy into 4 bags. How much candy will go in each bag?

almond37 [142]

Answer:

1/8 or 8

Step-by-step explanation:

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3 years ago

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Assoli18 [71]

Answer:

Step-by-step explanation:

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3 years ago

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

Papessa [141]

Answer:

The value of c is 2√2 or about 2.8.

Step-by-step explanation:

We can find the hypotenuse (c) with the help of Pythagoras Theorem.

=> c² = 2² + 2²
=> c² = 4 + 4
=> c² = 8
=> c = √8
=> c = √2 x 2 x 2
=> c = 2√2

If you want further simplification, seek for explanation below.

=> c = 2√2
=> c = 2 x √2
=> c = 2 x 1.414
=> c = 2.828 = 2.8 (Estimated)

Hence, the value of c is 2√2 or about 2.8.

Hoped this helped.

$BrainiacUser1357$

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2 years ago

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Answer:

$t=\frac{26.8-29.9}{\frac{2.7}{\sqrt{9}}}=-3.44$

$df=n-1=9-1=8$

$p_v =P(t_{(8)}$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and is not enough evidence to conclude that the claim is true.

Step-by-step explanation:

Data given

$\bar X=26.8$ represent the sample mean

$s=2.7$ represent the sample standard deviation

$n=9$ sample size

$\mu_o =29.9$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean exceed 29.9 or no, the system of hypothesis would be:

Null hypothesis: $\mu \geq 29.9$

Alternative hypothesis: $\mu < 29.9$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{26.8-29.9}{\frac{2.7}{\sqrt{9}}}=-3.44$

P-value

The degrees of freedom are given by:

$df=n-1=9-1=8$

Since is a one sided test the p value would be:

$p_v =P(t_{(8)}$

Conclusion

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and is not enough evidence to conclude that the claim is true.

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4 years ago