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dolphi86 [110]
2 years ago
7

If there are 500 students and 46% are male what is the percentage of female?

Mathematics
1 answer:
scoundrel [369]2 years ago
5 0

Answer:

Step-by-step explanation:

if you have :

500 students

46% male

500*(46/100)=230 students are male

500-230=270 female

(270*100)/500=54%

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As part of a drug trial, a survey was done to gather information about the participants' experiences with side effects. Here are
Paraphin [41]

The Venn diagram which represents the distribution of the participant in the drug trial is attached below. The Number of participants in the drug trial that has anxiety is 370

We can find the number of participants who has dizziness(D). Fatigue(F) and anxiety(A) can be calculated thus :

n(D) = n(D only) + (DnF only) + (DnA only) + (DnAnF)

271 = 36 + 86 + 23 + x

271 = 145 + x

x = 271 - 145

x = 126

  • n(DnAnF) = 126

<u>Number who has </u><u>atleast one of the three</u><u> side effects can be expressed thus</u> :

n(A only) + n(F only) + n(D only) + (DnF only) + (DnA only) + (DnAnF) + n(FnA only) = 585

36 + 23 + 62 + 86 + 126 + 93 + n(FnA) only = 585

  • n(FnA only) = 585 - 426 = 159

<u>Number of participants</u><u> who has </u><u>anxiety</u><u> can be calculated thus</u> :

n(DnAnF) + (DnA only) + n(FnA only) + n(A only)

126 + 23 + 159 + 62 = 370 participants

Therefore, 370 of the total participants has Anxiety.

Learn more : brainly.com/question/12570490

8 0
2 years ago
Monica and Lauren know that they will need a lot of money in order to make the purchases necessary for a successful bakery. They
xxTIMURxx [149]

Based on the model, the total amount of money in the joined account after the 5 weeks is $767.30

<h3>What are linear equations</h3>

Linear equations are equations that have constant rates

A linear equation is represented as:

y = mx+ b

In this case,

  • m represents the deposit per week
  • b represents the initial deposit

So, the linear equations are:

  • y =153.46x --- for Monica
  • y = 128.90+ 127.68x -- For Lauren

To calculate the number of weeks, when they have the same amount, we equate both equations

153.46x = 128.90 + 127.68x

Collect like terms

153.46x -127.68x= 128.90

25.78x= 128.90

Solve for x

x= 5

Substitute 5 for x in

y = 153.46x

y = 153.46 * 5

y = 767.30

Hence, it will take 5 weeks for both accounts to have the same amount of $767.30

Read more about linear equations at:

brainly.com/question/14323743

4 0
2 years ago
find the circumference and the area of the circle with the radius 9m use the value 3.14 for it do not round your answer be sure
kirill [66]

Explanation:

The circumference and the are of a circle with radius r

are:

\begin{gathered} A=\pi r^2 \\ C=2\pi r \end{gathered}

If we use pi = 3.14 and the radius is 9m:

A=3.14\cdot(9m)^2=3.14\cdot81m^2=254.34m^2C=2\cdot3.14\cdot9m=56.52m

Answers:

• Area: ,254.34 m²

,

• Circumference: ,56.52 m

7 0
10 months ago
Solve for the roots in the equation below. x4 + 3x2 - 4 = 0
fgiga [73]
First, you need to rewrite the expression into binomial form, so you are working with two terms (as you world with a quadratic):
(x²)²-3(x²)-4=0
Now, you can place the x²s into brackets as the coefficient is now 1:
(x²  )(x²  )
Next, find out two numbers that add together to give you -3 and multiply to give -4 (these are the leftover integers after removing the x²s). These two numbers are -4 and 1.
Place the -4 and 1 into the brackets:
(x²-4)(x²+1)=0
Notice that the x²-4 is a difference of two squares, so can be further factorised into (x+2)(x-2)
This leaves you with a final factorisation of:
(x+2)(x-2)(x²+1)=0
Now we handle each bracket individually to obtain our four solutions for x:
x+2=0
x=-2
x-2=0
x=2
x²+1=0
x²=1
x=<span>±1</span>

8 0
3 years ago
Let f(t) ANSWER: 1+ = t² - 1 t+3 Find f'(1)​
Luda [366]

Answer:

f(1) = 3

Step-by-step explanation:

f(t) = t² - 1t + 3

we want to find f(1)

all we have to do is replace the t's with 1 and evaluate

f(1) = (1)² - 1(1) + 3

evaluate exponent 1² = 1

f(1) = 1 - 1(1) + 3

multiply

f(1) = 1 - 1 + 3

subtract

f(1) = 3

4 0
1 year ago
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