Answer:
<h2>
<em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>D</u></em></h2>
Step-by-step explanation:
As,
![{64}^{ \frac{2}{3} } = {(\sqrt[3]{64})}^{2} = \sqrt[3]{ {64}^{2} }](https://tex.z-dn.net/?f=%20%7B64%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%20%3D%20%20%7B%28%5Csqrt%5B3%5D%7B64%7D%29%7D%5E%7B2%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B64%7D%5E%7B2%7D%20%7D%20%20)
B. D represents the amount of dimes and q represents the amount of quarters so that equals 20 coins total. 0.25q is the amount of quarters multiples by their cost, when added to 0.1d it equals 4.25.
First, let's use the given information to determine the function's amplitude, midline, and period.
Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.
Finally, we should determine the parameters of the function's formula by considering all the above.
Determining the amplitude, midline, and period
The midline intersection is at y=5 so this is the midline.
The maximum point is 1 unit above the midline, so the amplitude is 1.
The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
Determining the type of function to use
Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.
This means there's no horizontal shift, so the function is of the form -
a sin(bx)+d
Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.
The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.
The midline is y=5, so d=5.
The period is 4π so b = 2π / 4π = 1/2 simplified.
f(x)1 sin 1/3x+5 = Solution
