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Leona [35]
3 years ago
9

Which of the following is true if YW is an angle bisector.

Mathematics
2 answers:
Semmy [17]3 years ago
8 0

Answer:

Third option is the correct answer

Step-by-step explanation:

\angle XYW\cong \angle ZYW

Sloan [31]3 years ago
3 0

Answer:

Step-by-step explanation:

Angle XYW is congruent to angle ZYW

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Find the value of x. 3x(5+2)=16
Iteru [2.4K]

Answer:

16/21

Step-by-step explanation:

We are given the equation 3x(5 + 2) = 16.

By order of operations, let's add the two numbers in the parentheses first:

3x(5 + 2) = 16

3x(7) = 16

Now, we must multiply 3x by 7:

3x * 7 = 16

21x = 16

Divide both sides by 21:

x = 16/21

The answer is thus 16/21.

<em>~ an aesthetics lover</em>

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4 years ago
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For a school assembly student sit in chairs that are arranged in 53 rows. There are 12 chairs in each row. About how many studen
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Do you go to connexus I have the same question?
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3 years ago
Which of the following sets is NOT closed under addition.
Veronika [31]

Answer:

Step-by-step explanation:

The odd numbers.

Suppose you have 31 and 27 when you add these two together, you get 58 which is not an odd number.

If you need a more mathematical proof, you could do it this way.

2x+1

2x is even. Anything multiplied by 2 is even. When you add 1 you get an odd number

So continue on

2y + 1 is the other number.

2x + 1 + 2y + 1 = 2(x + y) + 2

2 (x + y ) is even. When you add 2 to it, nothing changes. The result is still even.

7 0
3 years ago
The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe
WARRIOR [948]

Answer:

7536 km^3/sec

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

Volume = \pi r^2h

Where r is the radius and

h is the height of cylinder.

As per question statement:

r = 40 km (variable)

h = 2.5 (constant)

\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h

As \pi, h are constant:

\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec

4 0
3 years ago
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