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gulaghasi [49]
3 years ago
7

The greenhouse club is purchasing seed for the lawn in the school courtyard. The club needs to determine how much to buy. Unfort

unately, the club meets after school, and students are unable to find a custodian to unlock the door. Anthony suggests they just use his school map to calculate the area that will need to be covered in seed. He measures the rectangular area on the map and finds the length to be 10 inches and the width to be 6 inches. The map notes the scale of 1 inch representing 7 feet in the actual courtyard. What is the actual area in square feet?
Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

???

Step-by-step explanation:

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Brums [2.3K]

Answer:

the answer I'd 1.008

Step-by-step explanation:

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I need help like really bad in the next 10 mins or I fail math please help me-
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A certain forest covers an area of 4600km. Suppose that each year this area decreases by 7.75%. What will the area be after 13 y
wolverine [178]

Answer:

1679.60\ km^2

Step-by-step explanation:

-We can use the exponential decay function to estimate the size after 13 years:

P_t=P_oe^{-rt}

Where:

P_t is the size after t years, t is the time, r is the rate of decay and P_o the original size.

#We substitute and calculate as:

P_t=P_oe^{-rt}\\\\=4600e^{-13\times 0.0775}\\\\=1679.60

Hence, the forest covers 1679.60\ km^2 after 13 years.

4 0
3 years ago
What is the factorization of the polynomial below<br>-x^2 - 15x - 56​
Andrej [43]

Answer:

Step-by-step explanation:

This is more easily understood if you take out a common factor of -1

-1(x^2 + 15x + 56)

7*8 = 56

7 + 8 = 56

-1 (x +8)(x+7)

3 0
3 years ago
The scatter plot shows a correlation between the years and the rainfall in centimeters in Tennessee.
nataly862011 [7]

Answer:

7

4

Step-by-step explanation:

The <u>actual values</u> are shown on the given graph as <u>blue points</u>.

The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.

From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43).  It appears that the regression line is at y = 50 when x is the year 2000.

⇒ Difference = 50 - 43 = 7 cm

<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.

From inspection of the graph, in the year 2003 the actual rainfall was 44 cm,  shown by point (2003, 40).  It appears that the regression line is at y = 40 when x is the year 2003.

⇒ Difference = 44 - 40 = 4 cm

<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>

3 0
2 years ago
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