Answer:
Thus, the velocity at the time of strike is same as the velocity at the time of projection.
Explanation:
Let a projectile is projected vertically upwards with a speed of u and reaches to the maximum height H.
At maximum height , the speed is zero and then the projective comes back on the ground.
Use the third equation of motion
Now let the velocity at the time of strike is v'.
Use third equation of motion, here initial velocity is zero.
Thus, the velocity at the time of strike is same as the velocity at the time of projection.
Answer:
The amplitude of the wave is 0.02 m.
Explanation:
Given that,
Maximum speed = 2.0 m/s
Maximum acceleration = 200 m/s²
We need to calculate the angular frequency
Using formula of angular frequency
Put the value into the formula
We need to calculate the amplitude of the wave
Using formula of velocity
Put the value into the formula
Hence, The amplitude of the wave is 0.02 m.
Answer:
impulse will be equal to 1.969 N-s
Explanation:
We have given mass of the golf ball m = 60.8 gram = 0.0608 kg
Horizontal speed of the ball is v = 32.4 m/sec
We have to find the impulse of the golf ball
We know that impulse is equal to momentum of the object
So we have to find the momentum of the object
Momentum of the object is equal to product of mass of the object and speed of the object
So
As momentum is equal to impulse so impulse will be equal to 1.969 N-s
The answer is D. Current.