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Nata [24]
3 years ago
12

in a two-body collision, a. momentum is always conserved. b. kinetic energy is always conserved. c. neither momentum nor kinetic

energy is conserved. d. both momentum and kinetic energy are always conserved.
Physics
2 answers:
tatiyna3 years ago
4 0
The answer is neither the momentum nor kinetic energy is conserved
Luden [163]3 years ago
3 0

The energy derived from the digestion of food is __________.

A.

kinetic energy

B.

inertia

(C)

momentum

D.

chemical energy

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How frequently do most coastal areas experience high tides?
Alex777 [14]

It doesn't matter where you are.  "Tides" happen twice (hi - lo - hi - lo) in about 24 hours and 50 minutes.  Anywhere.

If it doesn't do two complete cycles in 24 hours 50 minutes, then it's not tide.

7 0
2 years ago
PLEASE HELP ME!!!!! You draw an arrow from left to right on a piece of paper and place the paper well behind a glass of water. Y
julia-pushkina [17]

Answer:

I think it is the first one: <u>The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.</u>

Explanation:

7 0
2 years ago
What is due to acids formed when atmospheric and volcanic gases mix with water
Ilya [14]

Answer:

Acid rain results when sulfur dioxide (SO2) and nitrogen oxides (NOX) are emitted into the atmosphere and transported by wind and air currents. The SO2 and NOX react with water, oxygen, and other chemicals to form sulfuric and nitric acids. These then mix with water and other materials before falling to the ground.

Explanation:

5 0
2 years ago
A baseball with a mass of 151 g is thrown horizontally with a speed of 39.5 m/s (88 mi/h) at a bat. The ball is in contact with
Oduvanchick [21]

Answer:

the average force exerted on the ball by the bat is 11,613.27 N

Explanation:

Given;

mass of the baseball, m = 151 g = 0.151 kg

initial velocity of the baseball, u = 39.5 m/s

final velocity of the baseball, v = 45.1 m/s

time of action, t = 1.10 ms = 1.10 x 10⁻³ s

The average force exerted on the ball by the bat is calculate as;

F = ma = \frac{m(v-u)}{t} \\\\F = \frac{0.151(45.1-(-39.5))}{1.10\times 10^{-3}} \\\\F = \frac{0.151(45.1\ +\ 39.5)}{1.10\times 10^{-3}} \\\\F = 11,613.27 \ N

Therefore, the average force exerted on the ball by the bat is 11,613.27 N

7 0
2 years ago
A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil and capp
Bond [772]

Answer:

= 925.92 N

≅ 926N

Explanation:

Pressure due to car = pressure due to applied force  

12000/18^2 = Force / 5^2

force = 12000 * 25/ 324

= 925.92 N

For equilibrium

Pressure1 = Pressure2

A1F1 = A2F2

12000*pi*(5^2) = F2 ( pi)*(18^2)

so, F2 = Applied force to lift car = 925.92 N

Pascal's principle

Pressure1 = Pressure2

F1/A1 = F2/A2 (F=force and A=area)

A1 =Pi*(0.05)²

A2 =Pi(0.18)²

F2=12000

F1 = 12000*(0.05)² / (0.18)² = 926N

7 0
3 years ago
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