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2 years ago

PLEASE HELP I NEED TO DO THIS BUT I DON’T KNOW HOW

1 answer:

7 0

Here is the answer but you didnt helped me to give a quadrilateral for solving according to my assummance i have done it if solution is ok then only give brainlest if it is wrong then re,ove the answer

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Ajutatima la ecuatia q*435=810

Alborosie

435 divided by 810 is 1.862068966. not rounded.

6 0

3 years ago

First person to give answer with work will get brainliest!!

Ket [755]

All you will have to do is put this inside of a graph and then see if it goes through the origin.

4 0

2 years ago

2(x + 8) = x + 20 help meeeeeeee !!!!! i need help

Ivenika [448]

Answer: x=4

Step-by-step explanation:

firstly you solve the barracks first by multipy 2 into ( x+8) after that you collect like terms on one side of the equation or make x become the subject of the equation and solve for x

7 0

2 years ago

Read 2 more answers

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3>Given :-</h3>

The right angled below is formed by 3 squares A, B and C
The area of square B has an area of 144 inches ²
The area of square C has an of 169 inches ²

We have to find the area of square A?

<h3>Let's Begin :- </h3>

The right angled triangle is formed by 3 squares

We have, 

Area of square B is 144 inches²
Area of square C is 169 inches²

We know that,

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

Subsitute the required values,

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

Area of square C = 169 inches

Let the side of square C be y

Subsitute the required values,

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3>Therefore, By using Pythagoras theorem, </h3>

The sum of squares of base and perpendicular height equal to the square of hypotenuse

That is,

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

Here, 

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

Subsitute the required values,

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3>Therefore,</h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

2 years ago

Graph the number on a number line sqrt 11

LekaFEV [45]

Sqrt 11 is approximately 3.31662479036

So make a line from about -5 to 5 and just estimate where that could be, between the numbers 3 and 4, make sure you mark that that is sqrt 11

6 0

2 years ago