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devlian [24]
3 years ago
12

Solve the inequalities by graphing. Select the correct graph. y > x y < -x

Mathematics
2 answers:
Vika [28.1K]3 years ago
5 0
My answer is x y because as the simulation show here y>x y <-× and because we are taking a way the x in this problem here I am assuming that the yas well have to be taking out as well for for the fact that is one we are subtracting from the x so we stay with x y it show you in the example y> / yx /<-x
Ksivusya [100]3 years ago
3 0

Answer:

The answer is in the attached image.

Step-by-step explanation:

In order to determine the graphing solution, you have to graph both inequalities, separately.

The region that is work for both inequalities is the solution. You can draw both equation and painting both, then the surface that it is painted by two colors is the region solution.

I have attached an image that show graphically the solution.

The blue region solution is for:

y>x

The green region solution is for:

y<-x

Therefore the region with the dark green is the solution for both.

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Ten less than three times the sum of x and seven is twenty-six.
Orlov [11]

Answer:

<u>x = 12</u>

Step-by-step explanation:

10 - 3 ( x + 7 ) = 26

<em>First Step: Distribute</em>

- 3 to ( x + 7 )

=  10 - 3 x - 21 = 26

<em>Second Step: Combine like terms</em>

10 - 21

=  - 11 - 3 x = 26

<em>Third Step: Add from both sides</em>

26 + 11

=  - 3 x = 37

<em>Fourth Step: Divide from both sides</em>

37 / - 3

<u>x = 12</u>

6 0
3 years ago
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
tia_tia [17]

p=501\cdot503\cdot\cdots\cdot597

q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601

So we have q=359,999p. Then

\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q

and the answer is D.

4 0
3 years ago
In rectangle ABCD, AB = 10 cm and BC = 14 cm. If rectangle EFGH is the image after a dilation, which could be its side lengths?
lana [24]

Answer is D

After dilation the image remain same but it is stretched or shrinked to the original size.

That means the ratio of the sides and the angles between the sides remain same .

Here we did dilation of ABCD which made it to EFGH.

Hence the ratio of the corresponding sides of the original rectangle ABCD should remain same even after dilation.

the corresponding sides are : AB and EF

BC and FG

CD and GH

DA and HE

* Let us find ratio of the sides AB and BC

given that AB= 10 and BC= 14

AB/BC= 10/14 = 5 /7 ( 10 and 14 both are multiple of 2 so we reduced them by a factor of 2 )

* the raio of the corresponding sides EF and FG should be same ( 5/7)

in the option D EF= 25 and FG= 35

so EF/FG= 25/35 = 5 /7 ( both are multiple of 5 so we reduced them by the factor of 5 )

Since ratio of the corresponding sides are coming out to be same for the EFGH given in option D it should be the dilation of the ABCD

4 0
3 years ago
Read 2 more answers
Heather wants to enlarge a 4 x 6 in picture using a scale factor of 1:3. What will be the dimensions of the picture after she en
salantis [7]
It should be 12×18. 1:3 means you take where it's at, at 1 and multiply it's size by 3.
5 0
3 years ago
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42 is 21% of what number
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\begin{array}{ccc}42&-&21\%\\x&-&100\%\end{array}\ \ \ \ \ |cross\ multiply\\\\21x=42\times100\\\\21x=4200\ \ \ \ \ |divide\ both\ sides\ by\ 21\\\\\boxed{x=200}\leftarrow answer
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3 years ago
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