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2 years ago

Solve the inequalities by graphing. Select the correct graph. y > x y < -x

Mathematics

2 answers:

Vika [28.1K]2 years ago

5 0

My answer is x y because as the simulation show here y>x y <-× and because we are taking a way the x in this problem here I am assuming that the yas well have to be taking out as well for for the fact that is one we are subtracting from the x so we stay with x y it show you in the example y> / yx /<-x

Ksivusya [100]2 years ago

3 0

Answer:

The answer is in the attached image.

Step-by-step explanation:

In order to determine the graphing solution, you have to graph both inequalities, separately.

The region that is work for both inequalities is the solution. You can draw both equation and painting both, then the surface that it is painted by two colors is the region solution.

I have attached an image that show graphically the solution.

The blue region solution is for:

y>x

The green region solution is for:

y<-x

Therefore the region with the dark green is the solution for both.

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Write an equation of the line that passes through the point (-6, -9) with slope-5.

Art [367]

Answer:

$y+9=-5(x+6)$

Step-by-step explanation:

We are being asked to write the equation in point-slope form:

$y-y_1=m(x-x_1)$ where m = slope and the first point = $(x_1,y_1)$

In this case, the slope is -5 and the point is $(-6,-9)$ so the equation will be:

$y+9=-5(x+6)$

Want to learn more about point-slope form? Check the link out:

https://www.albert.io/blog/point-slope-form/#What_is_point_slope_form

3 0

2 years ago

For f(x)=1/x^2-3

igomit [66]

For f(x)=1/x^2-3

Find

A) f(3)

B) f(2-h)

If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9

If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:

f(2-h) = ------------------ - 3

4-4h +h^2

5 0

2 years ago

The coordinates below represent two linear equations.

vovikov84 [41]

First write the equations in the slope-intercept form:
$y=mx+b \\ \\
m=\frac{y_2-y_1}{x_2-x_1}$

Line 1 passes through the points (-6,-6) and (-4,-3).
$m=\frac{-3-(-6)}{-4-(-6)}=\frac{-3+6}{-4+6}=\frac{3}{2} \\ \\
(-6,-6) \to x=-6, \ y=-6 \\
-6=\frac{3}{2} \times (-6) + b \\
-6=-9+b \\
b=3 \\ \\ y=\frac{3}{2}x+3$

Line 2 passes through the points (0,3) and (2,6).
$m=\frac{6-3}{2-0}=\frac{3}{2} \\ \\
(0,3) \to x=0, \ y=3 \\
3=\frac{3}{2} \times 0 + b \\
b=3 \\ \\
y=\frac{3}{2}x+3$

These are two identical lines so the system of equations has infinitely many solutions. The answer is D.

7 0

3 years ago

Read 2 more answers

The volume of a cone is represented by the formula V = 1 T?n. If the volume of a cone is 30rt and the height is 2.5, what is the

Airida [17]

Answer:

radius is 3.38cm

Step-by-step explanation:

Note: the volume of a cone is given as

$V= 1/3 \pi r^2 h$