If x is the hypotenuse then
hyp^2 = 4^2 + 5^2
hyp^2 = 41
hypotenuse =
<span>
<span>
<span>
6.403124
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if x is a leg then
leg^2 = 5^2 - 4^2
leg^2 = 25 - 16
leg^2 = 9
leg =3
B.) 81
sq rt of x= 12-3
sq rt of x=9
take the ^2 of both sides to get rid of the sq root
x^2= (9)^2
=81
Answer:
F) standard form
Step-by-step explanation:
Answer:
101
Step-by-step explanation:
To figure this out, you would do 167 - 66 = 101
101 + 66 = 167
The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π
<h3>The circle with center P</h3>
Given that the circle has a center P
It means that lengths PQ, PR, PS and PT
From the question, we understand that QR = ST.
This implies that triangles QRP and STP are congruent.
i.e. △QRP ≅ △STP is true
<h3>The length of the minor arc</h3>
The given parameters are:
Angle, Ф = 99
Radius, r = 1
The length of the arc is:
L = Ф/360 * 2πr
So, we have:
L = 99/360 * 2π * 1
Evaluate
L = 198/360π
Divide
L = 11/20π
Hence, the length of the minor arc is 11/20π
Read more about circle and arcs at:
brainly.com/question/3652658
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