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djyliett [7]
3 years ago
5

2) To cook a cake, Roberta Alberta bought 54.8 grams of butter. Then she found out that she bought

Mathematics
1 answer:
elena55 [62]3 years ago
3 0
Answer: 48.687 grams

Explanation: You subtract the amount of “extra” butter (6.113) from the amount she bought (54.8). Brainliest??!
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dem82 [27]

Answer:

The inequality is 6 + 3x ≤ 12 or x ≤ 2 .

Step-by-step explanation:

Given that $6 is for admission which is a fixed amount, $3 is charged per hour and must not spend more than $12. So the inequality will be :

Let x be the no. of hours,

6 + 3x ≤ 12

Solve :

6 + 3x ≤ 12

3x ≤ 12 - 6

3x ≤ 6

x ≤ 6 ÷ 3

x ≤ 2

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3 years ago
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liq [111]

Answer:

that is an addition sign  the correct answer is B

Step-by-step explanation:

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This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

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6 square feet in each roll
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Draw a picture of a figure that has more than 3 lines of symmetry. Draw the lines of symmetry
scZoUnD [109]

Answer: A hexagon has 6 lines of symmetry.

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