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Leni [432]
3 years ago
7

Hurrrrrrrryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
7 0

Answer:

i think its x= 18 degrees but i dont know so i apologize if its wrong

Step-by-step explanation:

Artyom0805 [142]3 years ago
7 0

Answer:

77 180-26=154 sence its iscosolice dived that by 2 154/2=77

Step-by-step explanation:

if brainiest is earned its greatly apprieciated

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Let's consider the time as a discrete variable with an increment of 1 minute. You arrive at a bus stop at 10 AM, knowing that th
Dafna11 [192]

Answer:

a) 2/3

b) 1/3

Step-by-step explanation:

Let X be the random event that measures the time you will have to wait.  

Since time is uniformly distributed between 10 and 10:30 in intervals of 1 minute

P(n < X ≤ n+1) = 1/30 for every minute n=0,1,...29.

a)

P( X > 10) = 1 - P(X ≤ 10) = 1 - 10/30 = 2/3

b)

P(10 <  X ≤ 20) = (20-10)/30 = 1/3

7 0
3 years ago
Triangle XYZ has vertices X(0,3), Y(2,0) and Z(4,2). if yo reflect triangle XYZ across the line x=4, what will be the coordinate
Paha777 [63]

As X' is the reflected point of X(0,3) , so the x co ordinate of X' = 0+8 =8 and here y co ordinate remains same.

So, X'= (8,3)

Like that way, Y' is the reflected point of Y(2,0) and Z' is the reflected point of Z(4,2)

As the point Z is lying on the line x=4 and the reflection is also across that line, so both Z and Z' represent same point.

Y'= (2+4, 0) = (6, 0)

Z' = (4, 2)

3 0
3 years ago
A triangle has an area of 15. One of its sides has length 10. What is the length of the altitude to that side?
UNO [17]

Answer:

Im to lazy to calculate the entire answer but its basically the formula is a*b/2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
An electrician charged a fee of $45 plus $60 per hour to come to Ed's house and make a repair. How many hours did the repair tak
viva [34]

Answer:

1 hour and 15 minutes

Step-by-step explanation:

$120 - $45 = $75

$75 ÷ $60 = 1.25 hours or and 1 hour and 15 minutes

5 0
3 years ago
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