Please help me with my homework my homework question
2 answers:
Answer:
(B) Subtract 3x from both sides of the equation, and then divide both sides by 2.
Can't read the second question fully.
(A) 0.53
Step-by-step explanation:
Number 1:
If we have the equation , our first goal is to get rid of the x term on one side.
To do this we can subtract 3x from both sides. This leaves our equation to . To find x, we want to divide both sides by 2 since 2x divided by 2 is just x. Our goal is to isolate x. This leaves
.
<em>I couldn't read Number 2 fully - I'm sorry :c</em>
<em></em>
Number 3:
Given the equation , we want to isolate x on one side.
To do this, we first apply the distributive property to the left side.
Now subtract 0.6 from both sides:
And divide both sides by 3.
This rounds to 0.53.
Hope this helped!
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Answer:
6m
Step-by-step explanation:
the side of first square = 3 m
area of first square = 3^2= 9 m^2
let the side of second square = x m
since diagonal of first square = x m as per the question
in a square each angle is 90 degree
therefore by applying pythagorus theorem ,
diagonal ^2 = side^2 + side ^2
diagonal^2 = 3^2+3^2=9+9
DIAGONAL= square root of 18
diagonal= 3 m = side of second square
therefore in second square ,
one angle is 90 degree , therefore by applying pythagorue theorem
diaqonal^2 = side ^2 + side ^2 = (3)^2 + ( 3
)^2
diagonal ^2 = 18 + 18
diagonal = square root of 36
therefore diagonal of second square is 6m
hope it helps you... please mark me as the brainliest..