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3 years ago

Can someone help me answer this

Mathematics

1 answer:

irinina [24]3 years ago

4 0

Answer:

if b = e??

what are the drop down options?

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Round 288 to the nearest tenth

cricket20 [7]

290

hopefully i could help ;)

6 0

3 years ago

Simplify and write the trig expression in terms of sin and cos

dsp73

We have:

$cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}$

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

$-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}$

We clear f(x):

$f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}$

we simply what we can:

$f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)$

Thus, the correct answer is;

$f(x)=sin(x)$

6 0

1 year ago

SOLVE FOR X ANSWER IN FRACTION FORM I DONT NEED TO SHOW WORK

ExtremeBDS [4]

Answer:

$x=\frac{27}{2}\:\text{or}\:13.5$

Step-by-step explanation:

Both triangles are shown are similar. Therefore, the ratio of their sides will be maintained. We can then set up the following proportion:

$\frac{2}{11}=\frac{3}{3+x},\\2(3+x)=33,\\(3+x)=16.5,\\x=\boxed{13.5\text{ or }\frac{27}{2}}$

5 0

2 years ago

ALOT OF POINTS IF YOU HELP ME PLEASE EXPLAIN

Svetllana [295]

Answer:

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).

Step-by-step explanation:

Misha's group was asked to write an expression equivalent to

7y²z + 3yz² - 3

When Mr. Chen checked their answers, he found only one to be correct.

And she was Helena.

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).

Because, (7y²z + 6yz²- 5 - 3yz² + 2)

= 7y²z + (6yz² - 3yz²) - (5 - 2)

= 7y²z + 3yz² - 3 (Answer)

4 0

3 years ago

Is anyone willing to help me with this? I tried adding this and still no answer. Please help..

GaryK [48]

Answer: C. (-4, -2)

Step-by-step explanation:

First, eliminate one of the variables and solve for the remaining variable:

2x - 5y = 2 → 3(2x - 5y = 2) → 6x - 15y = 6

3x + 2y = -16 → -2(3x + 2y = -16) → -6x - 4y = 32

-19y = 38

y = -2

Next, replace "y" with -2 into either of the original equations to solve for x:

2x - 5y = 2

2x - 5(-2) = 2

2x + 10 = 2

2x = -8

x = -4

x = -4, y = -2

Check:

Plug in the x- and y-values into the other original equation:

3x + 2y = -16

3(-4) + 2(-2) = -16

-12 + -4 = -16

-16 = -16 $\checkmark$

3 0

3 years ago