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MArishka [77]
3 years ago
9

What is the exponential form of the logarithmic equation? 3=log0.6 0.216

Mathematics
2 answers:
tatuchka [14]3 years ago
3 0

Answer:

0.216 = 0.6³

Step-by-step explanation:

using the rule of logarithms

• log_{b} x = n ⇔ x = b^{n}

log_{0.6} 0.216 = 3 ⇒ 0.216 = 0.6^{3}


slega [8]3 years ago
3 0

Answer:

(0.6)^3= 0.216

Step-by-step explanation:

3=log_{0.6} 0.216

To convert log form into exponential form we use a rule

if \ x=log_b(a) \ then \ b^x=a

WE apply this rule to convert log form in to exponential form

3=log_{0.6} 0.216

The base of log becomes the base of the exponent

(0.6)^3= 0.216

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Solve for each variable.
dem82 [27]

Answer:

a = 38⁰

b = 54⁰

c = 54⁰

Step-by-step explanation:

a + 142⁰ = 180⁰ because a straight line = 180⁰

b + 38⁰ + 88⁰ = 180⁰ because the angles of a triangle equal 180⁰, and the missing measurement = 38⁰ because it is a vertical angle to angle a

c + 88⁰ = 142⁰ because the angles are corresponding angles

5 0
3 years ago
What is the range of the graph above?
Juli2301 [7.4K]
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Nata [24]

Answer:

its a for 6, b for 7, and a for 8

Step-by-step explanation:

heress how i did it  ₙₓₙ⁺⁽°⁴₊₋²₆ÜààÆŒ

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%7Bx%7D%5E%7B2%7D%20%2B%204x%20-%205" id="TexFormula1" title="f(x) = {x}^{2}
frutty [35]

The inverse function theorem says

\dfrac{\mathrm df^{-1}}{\mathrm dx}(16)=\dfrac1{\frac{\mathrm df}{\mathrm dx}(f^{-1}(16))}

We have

f(x)=x^2+4x-5

defined on x>-2, for which we get

f^{-1}(x)=-2+\sqrt{x+9}

and

f^{-1}(16)=-2+\sqrt{16+9}=3

The derivative of f(x) is

f'(x)=2x+4

So we end up with

\dfrac{\mathrm df^{-1}}{\mathrm dx}(16)=\dfrac1{\frac{\mathrm df}{\mathrm dx}(3)}=\dfrac1{10}

6 0
3 years ago
What is the length of AC?
sladkih [1.3K]
When the question says that triangle ABC ~ triangle DEF, that means the triangles are similar. This means that their proportions are the same.
In triangle ABC, side length AB is the equivalent of side length DE in triangle DEF.

Since the proportions must be the same, we can take the known side from triangle ABC, find the equivalent of it on triangle DEF, and find the proportions.
We already found that side length AB ~ side length DE.
Now we can divide the lengths to find the proportions.
28 / 8 = 3.5
This means that each side on triangle ABC will be 3.5 times greater than the equivalent side on triangle DEF.

The length of AC in triangle ABC is 3.5 times the length of DF in triangle DEF.
Side length DF is 10.
Multiply 3.5 by 10 to get the length of AC.
3.5 • 10 = 35
So the length of AC is 35 units.

Answer:
Side length AC in triangle ABC is 35 units.

Hope this helps!
7 0
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