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grigory [225]
3 years ago
14

**50 pts**I mark brainliest** M<2=34 degrees. find m<4 and explain how you know.

Mathematics
2 answers:
stira [4]3 years ago
6 0

Answer:

angle 4 = 34 degrees

Step-by-step explanation:

angle 4 is equal to angle 2 because it is an alternate interior angle of 34 degrees.

agasfer [191]3 years ago
6 0

Answer:

34

Step-by-step explanation:

<1+<2=180° because these are neighbour angle

X+34=180

X=146

Then you can apply the left side

X+146=180

X=34

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Y/x^2 + y/x^3<br><br>perform the operation and express your answer as a single fraction​
umka2103 [35]

Answer:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

Step-by-step explanation:

Given the expression

\frac{y}{x^2}+\frac{y}{x^3}

Let us perform the operation and express your answer as a single fraction​

\frac{y}{x^2}+\frac{y}{x^3}=\frac{x^3y+x^2y}{x^5}

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Therefore, we conclude that:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

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Six more than five times a number x is at least twenty one
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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0
3 years ago
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