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3 years ago

Help me please and thank you

Mathematics

2 answers:

fiasKO [112]3 years ago

5 0

Since the triangles are the same, just flipped that means that all angles and segments are the same as well

I'm not sure if that's the "correct" way to prove it but that's why they're equal

Nonamiya [84]3 years ago

3 0

Answer:

Step-by-step explanation:

In ΔEGF & ΔEGH,

EF ≅ EH {given}

FG ≅ HG { midpoint theorem}

EG ≅ EG {Reflexive property}

ΔEGF ≅ ΔEGH { S S S congruent }

∠1 ≅ ∠2 {Corresponding parts of congruent triangles are equal}

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The quadratic function f(x)=ax^2+4x+c has a maximum at the point (1, 9) . What are the values of a and c?

valina [46]

Answer: a = -2 and c = 7

Step-by-step explanation:

(this answer uses some basic calculus)

We know that $f'(x) = 2ax + 4$ , and since $(1,9)$ is a maximum of $f$ , then $f'(1) = 0$ . That means $2a + 4 = 0$ , so $\boxed{a = -2}$ . Then since $f(1) = 9$ , we have $-2(1)^2 + 4(1) + c = 9$ , so $\boxed{c = 7}$ .

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2 years ago

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Pls help if you only know the answer thanks! :)

Ksju [112]

Answer:

C-0.1

Step-by-step explanation:

0.1 is between -3.8 and 0.

Hope can help you.

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3 years ago

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Paul would like to spend $700 on a vacation. He will sell some of his stock to pay for the vacation. If the stock is worth $32 p

BigorU [14]

700/32 = 21.875

He'd have to sell approximately 22 shares to have enough to pay for his vacation.

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3 years ago

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A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500

Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking, $\frac{d(w)}{dt}$ = 3 ft/sec

Rate at which the man is walking, $\frac{d(m)}{dt}$ = 2 ft/sec

Collective rate of both, $\frac{d(m+w)}{dt}$ = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min = 20 min

Now,

Distance traveled by man and woman are $m$ and $w$ ft respectively.

⇒ $m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft$

⇒ $w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\ ft$

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate $\frac{dh}{dt}$ .

Lets calculate h.

Applying Pythagoras formula.

⇒ $h^2=(m+w)^2+500^2$

⇒ $h=\sqrt{(2400+2700)^2+500^2} = 5124.45$

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ $h^2=(m+w)^2+500^2$

⇒ $2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt} + \frac{d(500)}{dt}$

⇒ $\frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}$ ...as $\frac{d(500)}{dt}= 0$

⇒ Plugging the values.

⇒ $\frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}$ ...as $\frac{d(m+w)}{dt} = 5$ ft/sec

⇒ $\frac{d(h)}{dt} =4.9761$ ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0

4 years ago

Chandler earns a base pay of $2,200 per month. He also earns a commission of 4% of his total sales . One month Chander earned $2

Kipish [7]

The answer is $333.33 hope it helps

8 0

3 years ago