Question

Please help me with this please!!!!!!

Answer 1

Best Answer: Look at the discriminant of the quadratic equations to find the number and type of solutions. The discriminant is part of the quadratic formula underneath the square root sign: b^2 - 4ac. If it is positive, then there are two real solutions for that quadratic equation. If the discriminant is 0, then there is one real solution. If the discriminant is positive, then there are two imaginary solutions.

1.) x^2 - 18 = 0
a = 1, b = 0, c = -18

b^2 - 4ac
(0)^2 - 4(1)(-18)
72

ANSWER: 2 real solutions

2.) x^2 + 5x + 7 = 0
a = 1, b = 5, c = 7

b^2 - 4ac
(5)^2 - 4(1)(7)
25 - 28
-3

ANSWER: 0 real solutions


Hope this helps

Answer 2

The value of the  discriminant b^2 - 4ac will tell you this :-

it =  5^2 - 4*1*7 = -3

which is negative 
Therfore there are no real number solutions

B