All categories

3 years ago

Someone help me with this one

Mathematics

1 answer:

Montano1993 [528]3 years ago

5 0

Answer:

p' (4,-2)

Step-by-step explanation:

P is at ( -1,5)

We are moving it 5 units to the right so add 5 to the x

We are moving it 7 units down so subtract 7 from the y

p'( -1+5, 5-7)

p' (4,-2)

You might be interested in

Help. will give brainliest. please hurry!!! <3

Arlecino [84]

Answer = 504 m2
Proof is below

7 0

2 years ago

I need to know this problem

Vaselesa [24]

C jdixixizi disused is

7 0

4 years ago

Read 2 more answers

What two expressions represent 3/12?

Goshia [24]

Answer:

A and C

3x1/12= 3/12

3x1/2= 3/12

5 0

3 years ago

Dont leave any links please

Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

$\displaystyle \large{ {(mn)}^{b} = {m}^{b} {n}^{b} } \\ \displaystyle \large{ {n}^{ - b} = \frac{1}{ {n}^{b} } }$

We are given the expression:

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } }$

Use the first law of exponent above.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) } } \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } {n}^{ - 1} }$

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n} } )} \\$

Multiply m in.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = \frac{ {m}^{2} }{ {n} } }$

Thus the answer is m^2/n.

6 0

3 years ago

Can you please simplify the fraction of 12/96

Serggg [28]

Answer: 1/8

Step-by-step explanation:

12 divided 12 1

———————- = —-

96 divided 12 8

4 0

4 years ago