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goldenfox [79]
2 years ago
15

A farmer sells 8.8 kilograms of apples and pears at the farmer's market. 3 /4 of this weight is apples, and the rest is pears. H

ow many kilograms of pears did she sell at the farmer's market?
Mathematics
1 answer:
gayaneshka [121]2 years ago
3 0

Answer:

  2.2 kg

Step-by-step explanation:

If 3/4 of the weight is apples, the remaining 1/4 is pears. 1/4 of 8.8 is 2.2, so ...

  the farmer sold 2.2 kg of pears at the farmer's market.

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Match the correct rational number to its equivalent repeating decimal: 27.33333
ExtremeBDS [4]

Answer:

A. \frac{82}{3}

Step-by-step explanation:

Step 1: We know .3333... is \frac{1}{3}, we rewrite the equation as  \frac{1}{3}

27\frac{1}{3}\\ \frac{1+(27)(3)}{3}\\\frac{1+81}{3}\\\frac{82}{3}\\

Therefore the answer would be A. \frac{82}{3}

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A= [1, 3; 2, 1], B=[3, 6; -1, 1]. Find AB & BA if possible
steposvetlana [31]

Answer:

AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}

Step-by-step explanation:

For two matrix P and Q, the product, say PQ is defined when:

The number of columns of P = The number of rows of Q

Since A is a 2×2 matrix and B is also a 2×2 matrix

Thus both AB and BA are possible.

So AB is:

AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}

BA is:

BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}

8 0
3 years ago
Find an equation for the line with slope m through the point (a,c).
lidiya [134]
If you want the answer in point slope form then,

y-y1 = m(x-x1)
y-c = m(x-a)

---------------------------------------

If you want the answer in slope intercept form, then solve for y

y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)

For this answer in slope intercept form the slope is m and the y intercept is c-ma

---------------------------------------

If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.

y = mx+c-ma
y-mx = mx+c-ma-mx
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Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.

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3 years ago
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natulia [17]

Answer:

78

Step-by-step explanation:

112-18-16=78

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