1) Take 18 and multiply it by 5 = 90
2) Then subtract 26 = 64
3) Then subtract 18 = 46
4) Then subtract 12 = 34
5) Then subtract 8 = 26
The answer is 26.
Answer:

Step-by-step explanation:
The formula for this equation is

a is the final result
p is the starting amount (deposited)
r is the interest rate
n is the number of times it's compounded
t is the time
because it says compound annually and it's after 2 years both t and n equal 2. I rounded a for you, but if you don't need it rounded here it is: 3863.345117
Please double check me I may be wrong, this is my second time doing these type of questions
Multilpy -2 on both sides of the < sign this will get u 1x < 24 in other words x < 24
Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then



has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Answer: 2/3ft or C
Step-by-step explanation: Solve for b in the area of a triangle equation, A=1/2bh. Multiply 1/2 by 2 on both sides to cancel it: A(2)=bh. Divide both sides by h:
=b
A = 2/5
h = 6/5
b = ?
Next, we can plug the numbers into this equation:
=b
Multiply 2 and 2/5: 4/5 / 6/5
Take the reciprocal of 6/5: 4/5 x 5/6 = 
÷
= 