r = 10/ sin (0) - cos (0)
The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
What is Quadratic equation?
An algebraic equation of the second degree is called a quadratic equation.
Given that;
A quadratic equation is;
3x² = -12x - 15
Now, The equation is written as;
3x² + 12x + 15 = 0
Take 3 common, we get;
3 (x² + 4x + 5) = 0
x² + 4x + 5 = 0
Factorize the equation by using Sridharacharya Formula;
x = - 4 ± √4² - 4*1*5 / 2*1
x = -4 ± √16 - 20 / 2
x = - 4 ± √-4 / 2
Since, √-1 = i
x = -4 ± 2i / 2
x = - 2 ± i
It gives two values of x as;
x = - 2 + i
And, x = - 2 - i
Hence, The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
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Answer:
y = -4
Step-by-step explanation:
-4y - 3 + 3y = 8 - 2y - 15
~Combine like terms
-y - 3 = -2y - 7
~Add 3 to both sides
-y = -2y - 4
~Add 2y to both sides
y = -4
Best of Luck!
Answer:
Is none a answer?
Step-by-step explanation:
They dont have a relashionship
First you need to find the common denominator. both 6 and 7 go in to 42 evenly
multiply 5/6 by 7 to get 35/42
multiply 2/7 by 6 to get 12/42
subtract 12 from 35 to get 23
23/42
