Answer: Find the probability that the number x of correct answers is fewer than 4 = 0.6087
Step-by-step explanation: Please find the attached files for the solution
7. There are 3 times as many adventure books as comic books in a bookshop. If there are 879 adventure books in the bookshop, how
many comic books are there?
8. Miss Flores had 216 colored beads, She asked Kristel to share them equally with 5 other friends, How many beads did Kristel get?
9. Ann made 450 hamburgers for a fun fair. She packed them equally into 7 boxes. How many hamburgers were there in each box? How many hamburgers were left?
8. Miss Flores had 216 colored beads, She asked Kristel to share them equally with 5 other friends, How many beads did Kristel get?
9. Ann made 450 hamburgers for a fun fair. She packed them equally into 7 boxes. How many hamburgers were there in each box? How many hamburgers were left?
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
The angles would be supplementary
45 + 5x + 35 = 180
5x + 80 = 180
5x = 100
x = 20
To find out why they are supplementary, refer to the transversal below
∠3 = ∠7 (corresponding angles)
∠8 = 180 - ∠7 (supplementary angles)
And since ∠7 = ∠3...
∠8 = 180 - ∠3 which is why (in the problem) those two angles are supplementary (adding to 180 degrees)
Answer:
y 0 1 2 3
P(Y=y) 0.0676 0.3549 0.3875 0.19
Step-by-step explanation:
P(Wed) = 0.26
P(Thurs) = 0.39
P(Fri) = 0.25
P(Sat) = 0.10
Y = No. of days beyond Wednesday it takes for both magazines to arrive i.e. 0,1,2,3
Y=0 means the magazines will arrive on Wednesday
Y=1 means the magazines will arrive till Thursday
Y=2 means the magazines will arrive till Friday
Y=3 means the magazines will arrive till Saturday
The possible combinations for Y are
Y(W,W) Y(W,T) Y(W,F) Y(W,S)
Y(T,W) Y(T,T) Y(T,F) Y(T,S)
Y(F,W) Y(F,T) Y(F,F) Y(F,S)
Y(S,W) Y(S,T) Y(S,F) Y(S,S)
So, we can classify these possible outcomes as Y=0,1,2,3.
Y(0) = Y(W,W) (both magazines take 0 days to arrive beyond Wednesday)
Y(1) = Y(W,T), Y(T,T), Y(T,W) (both magazines take 1 day to arrive beyond Wednesday)
Y(2) = Y(W,F), Y(T,F), Y(F,F) Y(F,W) Y(F,T) (both magazines arrive till Friday)
Y(3) = Y(W,S), Y(T,S), Y(F,S), Y(S,W), Y(S,T), Y(S,F), Y(S,S) (both magazines arrive till Saturday)
To calculate the PMF, we need to calculate the probability for each of the points in Y(0,1,2,3).
Y(0) = Y(W,W)
= 0.26 x 0.26
Y(0) = 0.0676
Y(1) = Y(W,T) + Y(T,T) + Y(T,W)
= (0.26 x 0.39) + (0.39 x 0.39) + (0.39 x 0.26)
= 0.1014 + 0.1521 + 0.1014
Y(1) = 0.3549
Y(2) = Y(W,F) + Y(T,F) + Y(F,F) + Y(F,W) + Y(F,T)
=(0.26 x 0.25) + (0.39 x 0.25) + (0.25 x 0.25) + (0.25 x 0.26) + (0.25 x 0.39)
= 0.065 + 0.0975 + 0.0625 + 0.065 + 0.0975
Y(2) = 0.3875
Y(3) = Y(W,S) + Y(T,S) + Y(F,S) + Y(S,W) + Y(S,T) + Y(S,F) + Y(S,S)
= (0.26 x 0.10) + (0.39 x 0.10) + (0.25 x 0.10) + (0.10 x 0.26) + (0.10 x 0.39) + (0.10 x 0.25) + (0.10 x 0.10)
= 0.026 + 0.039 + 0.025 + 0.026 + 0.039 + 0.025 + 0.010
Y(3) = 0.19
y 0 1 2 3
P(Y=y) 0.0676 0.3549 0.3875 0.19
The PMF plot is attached as a photo here.
