Answer:
To complete the problem statement it is needed:
1.- the volume and weight capacity of the truck, because these will become the constraints.
2.- In order to formulate the objective function we need to have an expression like this:
" How many of each type of crated cargo should the company shipped to maximize profit".
Solution:
z(max) = 175 $
x = 1
y = 1
Assuming a weight constraint 700 pounds and
volume constraint 150 ft³ we can formulate an integer linear programming problem ( I don´t know if with that constraints such formulation will be feasible, but that is another thing)
Step-by-step explanation:
crated cargo A (x) volume 50 ft³ weigh 200 pounds
crated cargo B (y) volume 10 ft³ weigh 360 pounds
Constraints: Volume 150 ft³
50*x + 10*y ≤ 150
Weight contraint: 700 pounds
200*x + 360*y ≤ 700
general constraints
x ≥ 0 y ≥ 0 both integers
Final formulation:
Objective function:
z = 75*x + 100*y to maximize
Subject to:
50*x + 10*y ≤ 150
200*x + 360*y ≤ 700
x ≥ 0 y ≥ 0 integers
After 4 iterations with the on-line solver the solution
z(max) = 175 $
x = 1
y = 1
This is the concept of volumes of solid figures;
To calculate for the volume of material required we calculate for the volume of the pyramid;
volume of the pyramid is given by:
volume=(length*width*height)/3
but in our case the base of the pyramid is square, therefore:
length=width=2 ft
height=6 ft
hence;
volume=(2*2*6)/3
volume=8 ft^3
The answer is 8 ft^3
To compare two fraction you need to rewrite the fractions so they have a common denominator.
1/2 should have been rewritten as 4/8
The answer is:
D. The fraction 1/2 should have been rewritten as 4/8.
5 : - 1/6 = 0.167 out of 10 = 1.67 out of 100 = 16.7
even number 0.33 out of 10:- 3.3 out of 100:- 33
a prime number 0.5 out of 10: 5 and out of 100:- 50
multipl of 3:- 0/33 out of 10:- 3.3 and out of 100: 33
