1) the types of number are the negative integers (e.g √-1 √-3 <span>√-5 are not defined)
2) the answer is No, proof: 2x</span>√-1 is not defined because <span>√-1 doesn't exist
3) the answer is No, proof: </span>√-1 - 3 is not defined because √-1 doesn't exist
4) the answer is Yes, proof: (√-1 )²= -1 this is a real number
5) the answer is No, proof: (√-1 )^3= (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist
6) the result would be defined with the following cases:
√-1+n, n>1
√-1xn, n<0
√-1/n, n<0
7) the result would not be defined with the following cases:
√-1+n, n<0
√-1xn, n>0
√-1/n, n>0
8) to square <span>3 + √-1, I use the method of complex number
i²= -1, it implies i= </span>√-1
so 3+√-1=3+i, and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1
9) it is used for finding complex roots of a number
117/6.5=18
speed= 18 feet per second
Hope it helped!
Answer:
6x^2-8x-64
Step-by-step explanation:
the answer for solving a quadrilateral
is base times height
so the base is 2x-8 and the height is 3x+8
(2x-8)(3x+8)
expand
6x^2-8x-64
Hope that helps :)
Please give brainliest
Answer:
there's no picture
Step-by-step explanation:
