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statuscvo [17]
3 years ago
10

Su has 3 times as many dolls as Bertha. When Su gives Bertha 4 dolls, they now have the same amount. How many dolls did they EAC

H have at the begining? How many did they EACH have at the end?
Mathematics
2 answers:
inna [77]3 years ago
7 0

I also think it would be 8
Usimov [2.4K]3 years ago
5 0

Answer: i believe its 8

Step-by-step explanation:

i say 8 because 3x4 is 12 and so if bertha orignally had 4 and was given 4 she would have 8 and if su had 12 and gave away four she would also have 8

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Software filters rely heavily on ""blacklists"" (lists of known ""phishing"" URLs) to detect fraudulent e-mails. But such filter
crimeas [40]

Answer:

a) X \sim Binom(n=16, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

The expected value is given by this formula:

E(X) = np=16*0.2=3.2

b) P(X=0)=(16C0)(0.2)^{0} (1-0.2)^{16-0}=0.02815

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Part a

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=16, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

The expected value is given by this formula:

E(X) = np=16*0.2=3.2

Part b

For this case we want this probability:

P(X=0)

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And using this function we got:

P(X=0)=(16C0)(0.2)^{0} (1-0.2)^{16-0}=0.02815

6 0
3 years ago
I need urgent help!!
RSB [31]

Answer: I don’t actually know sorry

Step-by-step explanation:

6 0
3 years ago
Find a fraction equivalent to 5/7 whose squared terms add up to 1184.
bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y  } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}

                                                              \large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \  \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28  } \end{gathered}$}

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The fraction that satisfies the request is \bf{\dfrac{20}{28}} , since in \bf{\dfrac{-20}{-28}} the negative signs are canceled and the first fraction is obtained.

3 0
2 years ago
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dem82 [27]

Answer:

i think the answer would be 35

6 0
2 years ago
Joey fills 1/5 of a toffee box in 1/25 of a
butalik [34]
1/25 of a minute is 2,4 secs.

1/5 = 2,4s
5/5 = 12 secs

5 0
4 years ago
Read 2 more answers
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