The product of a rational number and an irrational number is an irrational
number.
The correctly completed proof is presented as follows;
To prove that 4·π is irrational, with the assumption that, 4·π = , where <em>b</em> ≠ 0. Which by isolation of π gives π = .
The right side of the equation is <u>irrational</u>, because the left side of the
equation is <u>irrational</u>, this is a contradiction.
Therefore, the assumption is wrong and the number 4·π is<u> irrational</u>.
Reasons:
The proof is presented as follows;
With the assumption that 4·π is rational, we have;
Where;
b ≠ 0
Making π the subject of the above formula, by isolating, it, we have;
The right side of the equation is rational, however, the left side of the
equation π is irrational, which results in a contradiction, therefore, the
product 4·π is an irrational number.
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