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Furkat [3]
3 years ago
6

A computer repairs service charges $50 for diagnosis and $per hour for repairs. Write a linear function that models this situati

on . help lol
Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

62

Step-by-step explanation:

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The graph of f ′(x) is continuous and increasing with an x-intercept at x = 5. Which of the following statements must be true?
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w

Step-by-step explanation:

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3 years ago
A game decreased in price by 1 5 . After the reduction it was priced at £48. What was the original price of the game?
vovikov84 [41]

Answer:

£63

Step-by-step explanation:

when we subtract 15 from 48 ,we get 63 which is the answer.

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3 years ago
HELP!!!<br><br><br> -1/2(b-6)=5
notsponge [240]

Answer:

<h2>b=-4</h2>

Step-by-step explanation:

<h3>-1/2b+3=5</h3><h3>-1/2=5-3</h3><h3> -1/2b=2×-2</h3><h2> b=-4</h2>
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3 years ago
Dalton takes a rectangular piece of fabric and cuts from one corner to the opposite corner. If the piece of fabric is 12 centime
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7 0
3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
Read 2 more answers
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