It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is 
Likewise, the number of ways a female student can be chosen from 48 females is 
.
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:
Answer:
Step-by-step explanation:
![\sqrt[3]{\frac{27t^{9} }{729} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B27t%5E%7B9%7D%20%7D%7B729%7D%20%7D)
27 is a perfect cube for 
and 729 is a perfect cube for 
![\sqrt[3]{\frac{3^{3} t^{9} }{9^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B3%5E%7B3%7D%20t%5E%7B9%7D%20%7D%7B9%5E%7B3%7D%20%7D%20%7D)
now you can pull out the numbers from under the root, for t (divide the exponent by 3)
now simply to
Answer:
3 : 1
Step-by-step explanation:
We have to compare the value of two sides.
Ratio of sides = 12 : 4 = 
= 3 : 1
Isolate the w. Note the equal sign. What you do to one side, you do to the other.
Add 3π to both sides
- 3π (+3π) + w = 2π (+3π)
w = 2π + (3π)
w = 5π
w = 5π is your answer
hope this helps
