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vazorg [7]
3 years ago
7

I need help on this questions. These sequences are hard.​

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Step-by-step explanation:

1. "List the first 9 terms of the sequence defined recursively by

Sₙ = Sₙ₋₂ · (Sₙ₋₁ − 1)

with S₁ = 2 and S₂ = 3"

The first two terms are provided.  To find the third term, substitute n = 3:

S₃ = S₃₋₂ · (S₃₋₁ − 1)

S₃ = S₁ · (S₂ − 1)

S₃ = 2 · (3 − 1)

S₃ = 4

Repeating this process, we get that the first nine terms of the sequence are:

2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

2. "Compute the value of ∑(k=1 to 8) Sk, where Sk is the same sequence as in the previous question."

All we have to do here is add up the first 8 terms:

2 + 3 + 4 + 9 + 32 + 279 + 8896 + 2481705

= 2490930

3. "Is the sequence from question 1 arithmetic, geometric, or neither?  Explain how you reach your conclusion."

If the sequence were arithmetic, it would have a common difference.  But the difference between 3 and 4 is not the same difference between 4 and 9.

If the sequence were geometric, it would have a common ratio.  But the ratio between 2 and 3 is not the same ratio between 3 and 4.

So the series is neither arithmetic nor geometric.

4. "Find the sum of the first 200 terms of the arithmetic sequence that begins: 12, 18, 24..."

The sum of the first n terms of an arithmetic sequence is:

S = n (a₁ + aₙ) / 2

where a₁ is the first term and aₙ is the nth term.

The nth term of an arithmetic sequence is:

aₙ = a₁ + d (n − 1)

where d is the common difference.

Here, the first term is 12, so a₁ = 12.  The common difference is 18 − 12 = 6.  So the 200th term is:

a₂₀₀ = 12 + 6 (200 − 1)

a₂₀₀ = 1206

The sum of the first 200 terms is:

S = 200 (12 + 1206) / 2

S = 121800

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ziro4ka [17]

The absolute value inequality can be decomposed into two simpler ones.

x < 0

x > -8

<h3></h3><h3>Which two inequalities can be used?</h3>

Here we start with the inequality:

3|x + 4| - 5 < 7

First we need to isolate the absolute value part:

3|x + 4| < 7 + 5

|x + 4| < (7 + 5)/3

|x + 4| < 12/3

|x + 4| < 4

The absolute value inequality can now be decomposed into two simpler ones:

x + 4 < 4

x + 4 > - 4

Solving both of these we get:

x < 4 - 4

x > -4 - 4

x < 0

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These are the two inequalities.

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6 0
1 year ago
Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

5 0
3 years ago
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Solve the system with elimination 4x+3y=1 -3x-6y=3
Nuetrik [128]

Answer:

x = 1, y = -1

Step-by-step explanation:

If we have the two equations:

4x+3y=1 and -3x - 6y = 3, we can look at which variable will be easiest to eliminate.

y looks like it might be easy to get rid of, we just have to multiply 4x+3y=1  by 2 and y is gone (as -6y + 6y = 0).

So let's multiply the equation 4x+3y=1  by 2.

2(4x + 3y = 1)\\8x + 6y = 2

Now we can add these equations

8x + 6y = 2\\-3x-6y=3\\

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5x = 5

Dividing both sides by 5, we get x = 1.

Now we can substitute x into an equation to find y.

4(1) + 3y = 1\\4 + 3y = 1\\3y = -3\\y = -1

Hope this helped!

5 0
3 years ago
Can someone please help me with these questions?
Dmitrij [34]

Expanded form is writing out everything and no simplifying.

A. c times c

B. t times t times t times t  

C. 2 times x times x times x  

D. 4 times 4 times h times h

E. 2 times 2 times 2 times l times l times l

F. a times a times a + 7 times b times b

Hope this helps :)

8 0
3 years ago
On a number line, point F is at 4, and point G is at -2. Point H lies between point F and point G. If the ratio of FH to HG is 3
Mademuasel [1]

Here, we are required to determine the point where point H lie on the number line.

The point H is at point 2.5 on the number line.

The distance between point F and G on the number line is:

4 - (-2) = 6 numbers on the number line.

And since the ratio of FH to HG is 3:9

  • Then, let point H be at no. X on the number line.

Therefore; FH/HG = (4 - x)/(x - (-2))

i.e 3/9 = (4 - x)/ (x +2).

By cross multiplication, 3x + 6 = 36 - 9x.

Therefore, 12x = 30

and, x = 2.5

Therefore, the point H is at point 2.5 on the number line.

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7 0
3 years ago
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