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harina [27]
3 years ago
5

16 is what percent of 50?

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
8 0

Answer:

16 percent of 50 = 32

hope this helps!

have a great day :D

vovikov84 [41]3 years ago
6 0

Answer:

32

Step-by-step explanation:

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Four less than the quotient of a number 1 and 5.
zhannawk [14.2K]

Answer:

Step-by-step explanation:

You should know that quotient is the result of division.

 

n/2

 

Four less than that would be subtracting.

 

(n/2) - 4 = 9

5 0
3 years ago
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What is the solution for x if x/8= -8
LuckyWell [14K]

Answer:

x=-1

Step-by-step explanation:

just like 8/8 is 1 the same concept only you add a negative

8 0
3 years ago
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Combine Like Terms and Eliminate Parenthesis.<br>5z-[2z-(13z+8)]
katen-ka-za [31]

We need to start from the innermost parenthesis and work our way out.

The first parenthesis is 13z+8. These are not like terms because one involves a variable, while the other is a constant term. Two terms are summable if they involve the same power(s) of the same variable(s).

So, we can take one step outwards, and we arrive to the square brackets. We have

2z-13z-8

and 2z and -13z are like terms, so we can sum them:

2z-(13z +8) = 2z-13z-8 = (2-13)z-8 = -11z-8

Finally we arrive to the whole expression, which is

5z-(-11z-8) = 5z+11z+8 = (5+11)z+8=16z+8

Because, again, 5z and 11z were like terms.

6 0
3 years ago
To gain access to his account, a customer using an automatic teller machine (ATM) must enter a four-digit code. If repetition of
VMariaS [17]
I’m not really much sure, I tried.
8 0
3 years ago
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


We subtract equation (2) from equation (1) to get,


11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


This implies that,


6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



We divide both sides by 3 to get,


d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
7 0
3 years ago
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