If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
Answer:
2x-10
Step-by-step explanation:
Multiply BOTH x and -5 by 2
Answer:
The graph is attached Below and the plotting is given below.
Step-by-step explanation:
Given:
-9x + 6y = 18
Solution:
To draw a line on a graph the required minimum two points but here we will have three points as point A, point B, and point C.
For point A
Put x = -4 in the given equation we get
-9×-4 + 6y = 18
6y = 18-36
∴ 
∴ Point A ≡ ( -4, -3 ).
For point B
Put x = -2 in the given equation we get
-9×-2 + 6y = 18
6y = 18 - 18
6y = 0
∴ 
∴ Point B ≡ ( -2, 0 ).
For point C
Put x = 0 in the given equation we get
-9×0 + 6y = 18
6y = 18
∴ 
∴ Point C ≡ ( 0, 3 ).
Now we have Point A ,B and C join it and you will have Line.
The goal is to solve for y. Start by subtracting 2x from both sides. This gives you 8y=-2x+16. Now just divide both sides by 8, which gives you y=-2/8x+16/8. Finally, simplify this to y=-1/4x+2.
Answer:
Step-by-step explanation:
Factor
2
out of
2
x
2
.
2
(
x
2
)
+
6
x
−
4
Factor
2
out of
6
x
.
2
(
x
2
)
+
2
(
3
x
)
−
4
Factor
2
out of
−
4
.
2
x
2
+
2
(
3
x
)
+
2
⋅
−
2
Factor
2
out of
2
x
2
+
2
(
3
x
)
.
2(
x
2
+
3
x
)
+
2
⋅
−
2
Factor
2
out of
2
(
x
2
+
3
x
)
+
2
⋅
−
2
.
2
(
x
2
+
3
x
−
2
)