Previous balance:
+ $481,47→ 11/30
- $300,00 → 11/02
- $68,99 → 11 / 10
- $45,00 → 11/15
- $72,75 → 11/17
----------------------------
+ $481,47 - $113,26 =
+ $368,21
new balance:
+ $481,47→ 11/30
- $300,00 → 11/02
- $

→ 11 / 10 for -$58,99
- $45,00 → 11/15
- $

→ 11/17 for $ 0
-------------------------------------------------------------------------------------
+ $481,47 - $196,01 =
+$285,46
Answer:
Let the number of children be c, and the number of adults be a.
c + a = 170 (total number of tickets)
Then the cost of each is: $5.90/child, $9.60/adult:
5.9c + 9.6a = 1269.40 (total sales)
Solving as 2 simultaneous equations, we first transform the first equation:
a = 170 - c
Substitute into the 2nd equation:
5.9c + 9.6(170 - c) = 1269.40
Solving gives c = 98, and a = 170 - 98 = 72. This means that 72 adult tickets were sold that day.
The answer is g to the question
Answer:
1) E
2) D
3) G
4) I
Step-by-step explanation:
1)
P = 2(l + w)
P = 2(3a + 3 + 8a - 12)
P = 2(11a - 9)
P = 22a - 18
2)
P = 22a - 18
P = 22(3) - 18
P = 66 - 18
P = 48
3)
P = a + b + c
P = 3b + 7 + 7b - 2 + 7b - 2
P = 17b + 3
4)
P = 17b + 3
P = 17(6) + 3
P = 102 + 3
P = 105