(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
Hey there! :) So first of all, I got 31.67 per second. The way I got my answer is first, I knew that 1 KM is 1000 Meters. So now, I multiplied 114 x 1000 which equals 114,000 Meters. Then, I figured out that 1 Hour has 3600 Seconds. Then I did 114,000 ÷ 3,600 and got 31.67 Seconds. And that is how I got the answer!
Hope it helps and it's the right answer & it's understandable! :D
A- It will be smaller, because we're finding a part of a number, and it's no more than 100 percent.
B- It would be greater. It's more than 100 percent, which accounts for the whole value, and goes even more.
Hope this helps!
Answer:
it would be 0.3 with bar notation
Step-by-step explanation:
<u>Given</u>:
Given that FGH is a right triangle. The sine of angle F is 0.53.
We need to determine the cosine of angle H.
<u>Cosine of angle H:</u>
Given that the sine of angle F is 0.53
This can be written as,
Applying the trigonometric ratio, we have;
----- (1)
Now, we shall determine the value of cosine of angle H.
Let us apply the trigonometric ratio 
, we get;
----- (2)
Substituting the value from equation (1) in equation (2), we get;
Thus, the cosine of angle H is 0.53
